The axis of symmetry of f(x) is:
On a coordinate plane, a vertical dashed line at (2, 0) is parallel to
the y-axis ⇒ 2nd answer
Step-by-step explanation:
The vertex form of a quadratic function is f(x) = a(x - h)² + k, where
- (h , k) are the coordinates of its vertex point
- The axis of symmetry of it is a vertical line passes through (h , 0)
- The minimum value of the function is y = k at x = h
∵ f(x) = a(x - h)² + k
∵ f(x) = (x - 2)² + 1
∴ a = 1 , h = 2 , k = 1
∵ The axis of symmetry of f(x) is a vertical line passes through (h , 0)
∴ The axis of symmetry of f(x) is a vertical line passes through (2 , 0)
∵ Any vertical line is parallel to y-axis
∴ The axis of symmetry of f(x) is a vertical line parallel to y-axis and
passes through (2 , 0)
The axis of symmetry of f(x) is:
On a coordinate plane, a vertical dashed line at (2, 0) is parallel to
the y-axis
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The key features of the above given functions are correctly matched to their corresponding definition.
<h3>Definition of terms</h3>
- Negative sections of the graph: They are the parts where the graph is below the x-axis. That is option C.
- End behaviour: This is what happens to the graph on the far left or far right. That is option E.
- Positive sections of the graph: This is the parts where the graph is above the x-axis. That is option D.
- Intercepts: This is the points where the graph crosses an axis. That is option B
- Relative extrema: This is the points of relative minimum or maximum in a graph. That is option A.
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<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
Becouse k and n are 'neighbours' so their sum are 180
so k=180-42=138
