Answer:
Buffalo mild wings offers the lowest price per wing ($0.83).
Step-by-step explanation:
Let us find unit price per buffalo wing of each restaurant.


Upon rounding our answer to nearest cent we will get,

Therefore, buffalo bills offers each wing for $0.88.


Upon rounding our answer to nearest cent we will get,

Therefore, buffalo mild wings offers each wing for $0.83.


Therefore, wingers offers each wing for $0.85.
We can see that buffalo mild wings offers the lowest price per wing that is $0.83 per wing.
Answer:
% area of the shaded region = 33%
Step-by-step explanation:
Radius of the middle circle = 7 cm
Radius of the inner circle = 4 cm
Area of the middle circle = πr²
= π(7)²
= 49π
Area of the inner circle = π(4)²
= 16π
Area of the shaded region= 49π - 16π
= 33π
Area of the outermost circle = π(10)²
= 100π
% area of the shaded region = 
= 
= 33%
Therefore, area of the shaded region is 33% of the complete logo.
We can always split a regular polygon with
sides into
triangles, whose base is the side of the polygon and whose height is the apothem of the polygon. So, the sum of the areas of all these triangles is

where
is the number of sides,
is the side length, and
is the apothem length.
So, you just need to plug you values in: in your case, you have 
So, the formula becomes

Answer: m<4 = 117 degrees
Step-by-step explanation:
Knowing that angle 1 is 63 degrees, we can look at the other angle on the same side of the line, angle 4.
Angles on one side of a line add to 180 degrees.
180 - 63 = 117
Answer: False.
Step-by-step explanation:
This says;
If we have an interval I, f(x) is increasing if, for any two x1, x2 such that:
x1 ∈ I and x2 ∈ I.
where x2 > x1, ----> f(x1) > f(x2).
An increasing function means that, if the value of x increases, also does the value of f(x).
Particularly, here we have that x2 > x1
so x can increase from x1 to x2.
But we have that f(x1) > f(x2)
So here we can see that the actual value of f(x) decreases as x increases.
Then this is not a increasing function, so the statement is false.