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quester [9]
3 years ago
8

For a t distribution with degrees of freedom, find the area, or probability, in each region. a. To the right of (to 3 decimals)

b. To the left of (to 2 decimals) c. To the left of (to 2 decimals) d. To the right of (to 2 decimals) e. Between and (to 2 decimals) f. Between and (to 2 decimals)

Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer:

a) P(t>2.120) = 0.025

b) P(t<1.337) = 0.90

c) P(t<-1.746) = 0.05

d) P(t>2.583) = 0.01

e) P(-2.120<t<2.120) = 0.95

f) P(-1.746<t<1.746) = 0.90

Step-by-step explanation:

The question is incomplete:

For a t distribution with 16 degrees of freedom, find the area, or probability, in each region.

a. To the right of 2.120. (Use 3 decimals.)

b. To the left of 1.337. (Use 2 decimals.)

c. To the left of -1.746. (Use 2 decimals.)

d. To the right of 2.583. (Use 2 decimals.)

e. Between -2.120 and 2.120. (Use 2 decimals.)

f. Between -1.746 and 1.746. (Use 2 decimals.)

We have a t-distribution with 16 degrees of freedom.

We can calculate the probabilities with a spreadsheet, a table or an applet.

We have to calculate the probabilities of:

a) P(t>2.120) = 0.025

b) P(t<1.337) = 0.90

c) P(t<-1.746) = 0.05

d) P(t>2.583) = 0.01

e) P(-2.120<t<2.120) = 0.95

f) P(-1.746<t<1.746) = 0.90

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Suppose that the demand Q^Dand supply Q^Sfor maize meal in Kimberley is given by p=120-0.7Q^Dand p=3+0.2Q^S where the quantity i
bixtya [17]

Answer:

  20 rands/kg

  130,000 kg

Step-by-step explanation:

The equilibrium quantity and price are the solution to the system of equations ...

  p = 120 -0.7q

  p = 3 + 0.2q

Setting these equal, we get ...

  0.2q +3 = p = -0.7q +120

  0.9q = 117 . . . . . . . add 0.7q-3 to both sides

  q = 117/0.9 = 130

  p = 3 +0.2·130 = 29

The equilibrium price of maize meal is 29 rands per kg; the market equilibrium quantity is 130,000 kg.

8 0
3 years ago
Help! Got it wrong after trying first time and need helppp !
finlep [7]

We are given the equation:

DA - 2qA = B³

Taking 'A' common on the LHS

A(D - 2q) = B³

Dividing both sides by (D - 2q)

A = B³ / (D - 2q)

5 0
2 years ago
A pathologist knows that 14.9% of all deaths are attributable to myocardial infarctions (a type of heart disease). (Either you h
garik1379 [7]

Answer:

a) The mean number is 745 and the standard deviation is 25.18.

b) 896 deaths is a significantly high number, which means that there is cause for concern.

Step-by-step explanation:

For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

A value X is significantly high is:

X > E(X) + 2\sqrt{V(X)}

In this problem:

p = 0.149, n = 5000

a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.

E(X) = np = 5000*0.149 = 745

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5000*0.149*0.851} = 25.18

The mean number is 745 and the standard deviation is 25.18.

b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?

Is 896 a significantly high number?

E(X) + 2\sqrt{V(X)} = 745 + 2*25.18 = 795.36

895 > 795.36

896 deaths is a significantly high number, which means that there is cause for concern.

6 0
3 years ago
Find the slope of the line between the ordered pair (−1,4)and(4,−1)
vekshin1

Answer:

Slope EQUALS: -\frac{6}{7}

Step-by-step explanation:

y=-x+3

4 0
2 years ago
I need help......,.................
Alexxandr [17]

Answer:B

Step-by-step explanation:

4 0
2 years ago
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