Find the least common multiple of the pair of polynomials. 2y^2-32 and y+4

What is the slope of the line passing through the points (-1,-7) and (-9, -2) ?

Dominik [7]

The equation for slope is:
(y2 - y1) / (x2 - x1)

-2 -(-7) = 5
-9 -(-1) = -8

Slope of the line:

5/-8 or -5/8

7 0

3 years ago

Cindy earned 35 bonus points. Farid earned b more bonus points than Cindy. Write an expression that shows how many bonus points

arlik [135]

# of points Farid has = b+35.

So the expression would be b+35.

4 0

3 years ago

Read 2 more answers

The function y = -3x + 5 is transformed by reflecting it over the y axis. What is the equation of the new function? *

SpyIntel [72]

Answer:

x= −1/3 y+5/3

Step-by-step explanation:

Let's solve for x.

y=−3x+5

Step 1: Flip the equation.

−3x+5=y

Step 2: Add -5 to both sides.

−3x+5+−5=y+−5

−3x=y−5

Step 3: Divide both sides by -3.

−3x

−3

=

y−5

−3

x=

−1

3

y+

5

3

4 0

3 years ago

If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro

yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

$\Rightarrow f(x) = 2\cos x + e^{2x}$

$\Rightarrow f'(x) = -2\sin x + 2e^{2x}$

And,

$\Rightarrow f(2) = 2\cos 2 + e^{4}$

$\Rightarrow f'(2) = -2\sin 2 + 2e^{4}$

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

$\Rightarrow y-y_1=m(x-x_1)$

$\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})$

The value of f(2.1) will be

$\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})$

$\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})$

$\Rightarrow y=64.5946$

According to given function, f(2.1) will be,

$\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}$

$\Rightarrow f(2.1) = 65.6766$

$\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%$

5 0

3 years ago

Ben spent 1/6 of his money on a burger, fries, and a drink. Then he spent half of the money he had left: $5 on a magazine, $8.25

Ket [755]

The amount of money Ben had to begin with after spending 1/6 and 1/2 of it is 57 dollars.

<h3>How to find the how much money he had with an equation?</h3>

let

x = amount he had to begin with

He spent 1/6 of his money on a burger, fries, and a drink. Therefore,

amount spent on burger, fries, and a drink = 1 / 6 x

Hence,

amount he had left = x - 1 / 6 x =6x - x /6 = 5 / 6 x

Then he spent half of the money he had left.

1 / 2(5 /6 x) = 5 + 8.25 + 10.50

5 / 12 x = 23.75

cross multiply

5x = 23.75 × 12

5x = 285

divide both sides by 5

x = 285 / 5

x = 57

Therefore, the amount of money he have to begin with is $57.

learn more on equation here: brainly.com/question/5718696

4 0

2 years ago