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3 years ago

Jean Paul laying in his bathroom. The room measured 10 feet in length and 6 feet in width. What is the area of the bathroom.

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

7 0

Answer:

6 x 10 = 60 ft.^2

(A = b h)

Step-by-step explanation:

Why is he laying on his bathroom floor/tub/whatever-

Area is base times height. (length times width, if you will)

10 x 6

=60

andriy [413]3 years ago

5 0

Answer:

60 ft^2

Step-by-step explanation:

6x10

get off of the bathrrom floor jean you sicko

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3 years ago

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3 years ago

Read 2 more answers

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

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