The histogram shows the ages of cars sold at a car auction. what percent of the cars was less than 20 years old or more than 40
years old? enter your answer in the box.
1 answer:
The histogram is attached. Every column shows on the bottom the range of age and on the left the number of cars of that particular age.
In order to find the percentage of cars with less than 20 years or more than 40 years, you have to sum up the numbers of cars in the first two columns from left (age 0-9 and 10-19) and the last two (age 40-49 and 50-59).
The number of cars of requested age is: 3 + 2 + 0 + 3 = 8
Now, you need to calculate the total number of cars (sum the cars of every column): 3 + 2 + 8 + 4 + 0 + 3 = 20
Lastly, you need to calculate the ration between the cars of requested age and the total number of cars, and transform it into a percentage:
8 ÷ 20 = 0.40 = 40%
Therefore, your answer is 40%.
In order to find the percentage of cars with less than 20 years or more than 40 years, you have to sum up the numbers of cars in the first two columns from left (age 0-9 and 10-19) and the last two (age 40-49 and 50-59).
The number of cars of requested age is: 3 + 2 + 0 + 3 = 8
Now, you need to calculate the total number of cars (sum the cars of every column): 3 + 2 + 8 + 4 + 0 + 3 = 20
Lastly, you need to calculate the ration between the cars of requested age and the total number of cars, and transform it into a percentage:
8 ÷ 20 = 0.40 = 40%
Therefore, your answer is 40%.
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Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°, ⊥
, AP = 9, and PM = 16
² +
² =
²
=
+ PM = 9 + 16 = 25
= 25
² =
² +
² = 9² +
²
∴ ² = 9² +
²
Similarly we get;
² = 16² +
²
Therefore, we get;
² +
² = 9² +
² + 16² +
² =
² = 25²
2·² = 25² - (9² + 16²) = 288
² = 288/2 = 144
= √144 = 12
From ² = 9² +
², we get
= √(9² + 12²) = 15
= 15
From, ² = 16² +
², we get;
= √(16² + 12²) = 20
= 20.