Answer:
C) x≥4 and x ≤ -4
Step-by-step explanation:
| 8x | ≥ 32
To remove the absolute values, we get two equations, one positive and one negative
8x ≥ 32 and 8x ≤ -32
Divide each side by 8
8x/8 ≥ 32/8 and 8x/8 ≤ -32/8
x ≥ 4 and x ≤ -4
Answer:
a) Minimize
subject to
b) Attached
c) The optimum value that minimizes cost is x1=28 and x2=8.
Step-by-step explanation:
The objective function is the cost of extraction and needs to be minimized.
The cost of extraction is the sum of the cost of extraction of ore type 1 and the cost of extraction of ore type 2:
Being x1 the tons of ore type 1 extracted and x2 the tons of ore type 2.
The constraints are the amount of minerals that need to be in the final mix
Copper:
Zinc
Magnesium
Of course, x1 and x2 has to be positive numbers.
The feasible region can be seen in the attached graph.
The orange line is the magnesium constraint. The red line is the copper constraint. The green line is the zinc constraint.
The optimal solution is found in one of the intersection points between two constraints that belong to the limits of the feasible region.
In this case, the cost can be calculated for the 3 points that satisfies the conditions.
The optimum value that minimizes cost is x1=28 and x2=8.
First divide the total by the amount bought.
$8.15/5 = $1.63
take the price per can and add $0.35 to add back on the usual price of tuna.
$1.98
The answer to the question is x=5
Answer:
ok i would help but im new so i dont know how to put it
Step-by-step explanation: