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Naily [24]
3 years ago
7

The direction of current in a solenoid depends on the direction of magnetic field’. Do you agree with this statement? Showthe pa

ttern of magnetic field lines of a solenoid through which a steady current flows. What does the pattern of field lines insidethe solenoid indicate

Physics
1 answer:
iogann1982 [59]3 years ago
7 0

Answer:

1) Yes the direction of the magnetic field is found based on Fleming's Right Hand Rule

2) The pattern indicates the direction of the magnetic force field lines

Explanation:

1) The solenoid is the is the coil of electric conductor that when it carries an electric current produces a magnetic field

According to Fleming's Right Hand Rule, the direction of the magnetic field produced by a solenoid, depends on the direction of the current such that when the direction of the conventional current is in the direction of the wrapped fingers, the thumb points in the direction of the magnetic field which is North N.

2) The pattern of field lines inside the solenoid indicates the direction of the generated magnetic field moving from left to right within the solenoid as the electric current moves around in the direction shown in the diagram.

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Two spherical objects are separated by a distance that is 9.00 X 10m The objects are initially electrically neutral and are very
romanna [79]

Answer: 3.2 * 10^-3 C

Explanation: In order to solve this problem we have to use the Coulomb force given by:

F=k*q^2/ d^2 where he consider the same charge for each point

so, we have

q^2= F*d^2/k= 1.137* (10 C*9*10m)^2/9*10^9 N*m^2/C^2)=3.2 * 10^-3 C.

5 0
3 years ago
Describe the possible long term impact of a catastrophic event
denpristay [2]
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4 0
3 years ago
calculate minimum number of incident photons per area and of the minimum dose needed to visualize an object of 1 mm squared usin
Lynna [10]

Answer:

minimum number of photon is 4.05 × 10^{7}

Explanation:

given data

energy = 50 keV = 50 × 10^{3} eV =  50 × 10^{3} × 1.602× 10^{-19}  J

thickness = 10^-3

contrast = 1%

to find out

number of incident photons

solution

we know here equation that is

E  = n  × h  × ν   .......................1

put here all these value

50 × 10^{3} = n × 6.6× 10^{-34} × c/ 1× 10^{-3}

50 × 10^{3} × 1.602× 10^{-19}  = n × 6.6× 10^{-34} ×( 3 × 10^{8} / 1× 10^{-3})

solve it and find n

n = 4.05 × 10^{7}

so here minimum number of photon is 4.05 × 10^{7}

3 0
3 years ago
By what percent does the braking distance of a car decrease, when the speed of the car is reduced by 10.3 percent? Braking dista
likoan [24]

The braking distance is the distance traveled by a car experiencing a braking force until it comes to rest.

Our initial energy is solely kinetic:
E_i = \frac{1}{2}mv^2

And, since the car goes to rest, it is no longer in motion. It will have no kinetic energy.
E_f = 0

Therefore, there was work done by the braking force.

W_B = E_f - E_i = -\frac{1}{2}mv^2

Recall the definition of work:
W = F\cdot \Delta x

Or in this case, since the displacement and breaking force are antiparallel:
W = -F_B\Delta x

This is equivalent to the dissipation of kinetic energy:
W = -F_B\Delta x = -\frac{1}{2}mv^2

Now, to visualize this, let's rearrange the equation to solve for displacement.

\Delta x =\frac{mv^2}{2F_B}

<u>There is a direct, SQUARE relationship between necessary braking distance speed. </u>

If the speed was reduced by 10.3 percent, its new speed is only 89.7% percent of the original, so:
\Delta x' =\frac{m(0.897v)^2}{2F_B}

\Delta x' = 0.8046\Delta x

The reduction by a percentage is:
1 - 0.8046 = 0.1954 \\\\\boxed{= 19.54\%}

6 0
1 year ago
How many light years away is the sun from the middle of the Millky way​
julsineya [31]

Answer:

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4 0
3 years ago
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