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Setler [38]
3 years ago
10

If any problem involving circular motion, which way does the acceleration vector point ?

Physics
1 answer:
KIM [24]3 years ago
4 0

Answer:

The acceleration vector always points towards the centre of the motion. This is referred to as centripetal acceleration. It accounts for the centripetal force that tends to pull the object in circular motion towards the centre of motion.

Consider the diagram below;

it illustrates a body in circular motion along the black circle, with the acceleration vector a shown by the orange arrow pointing towards the centre of motion and the velocity vector v shown by the green arrow pointing tangentially away from the circumference.

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What is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second?
bagirrra123 [75]

Answer:

500 J

Explanation:

Kinetic Energy = (mass x velocity x velocity) ÷ 2

We know that mass = 10 kg and velocity = 10 m/s.

KE = (m × v × v) ÷ 2

KE = (10 kg × 10 m/s × 10 m/s) ÷ 2

KE = 500 J

The kinetic energy of the object is 500 J (joules). Hope this helps, thank you !!

5 0
3 years ago
What determines color in the visible light region of the electromagnetic spectrum?
anyanavicka [17]

Answer:

In the electromagnetic spectrum, "Blue" is the "highest" frequency color of visible light.

Or In the electromagnetic spectrum, "Red" is the "Lowest" frequency color of visible light.

Hope this helps!

7 0
4 years ago
A magnetic field would be produced by a beam of
kumpel [21]
3 protons should be your answer
4 0
3 years ago
If the momentum of a 1000 kg car travelling at 10 m/s was transferred completely to a 20.0 kg traffic barrier, what would the fi
denis-greek [22]

Answer:

d. 500 m/s

Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

deduced from the question,

Momentum of the car = momentum of the barrier.

MV = mv ............................. Equation 1

Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

v = MV/m........................ Equation 2

Given: M = 1000 kg, V = 10 m/s, m = 20 kg.

Substitute into equation 2

v = 1000(10)/20

v = 500 m/s.

Hence the speed of the barrier = 500 m/s

The right option is d. 500 m/s

8 0
4 years ago
A piece of gum is stuck to the outer edge of a horizontal turntable, which is revolving at a constant speed. The shadow of the g
cestrela7 [59]

Answer:

angular frequency of the table must be same as the frequency of the projection of the gum on the wall

Explanation:

Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table

So here we will say

y = R sin\theta

so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating

So we can say

\theta = \omega t

so here we can say

y = R sin(\omega t)

so here we can say that

angular frequency of the table must be same as the frequency of the projection of the gum on the wall

7 0
3 years ago
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