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3 years ago

7

Symptoms of excessive stress include all of the following EXCEPT:

1 answer:

sweet-ann [11.9K]3 years ago

6 0

Answer:

Symptoms of excessive stress include all of the following EXCEPT: increased energy level.

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What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach

Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$I(\tau)=0.051 A$

b

$I(3 \tau)=0.076 A$

c

$I_c= 0.08 A$

Explanation:

From the question we are told that

$I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R$

From the question we are told to find $I(\tau)$ when t=0 equals the time constant ( $\tau$ )

That is to obtain $I(\tau)$ .This is mathematically represented as

$I(\tau = t) = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })$

Substituting 12 V for $\epsilon$ and 150Ω for R

$I(\tau) = \frac{12}{150} (1- e^{-1})$

$=0.051 A$

From the question we are told to find $I(3 \tau)$ when t=0 equals the 3 times the time constant ( $\tau$ )

That is to obtain $I(3\tau)$ .This is mathematically represented as

$I(\tau = t) = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })$

$I(\tau) = \frac{12}{150} (1- e^{-3})$

$=0.076 A$

As tends to infinity $\frac{\infty}{\tau} = \infty$

So $I_c$ would be mathematically evaluated as

$I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})$

$= \frac{12}{150}$

$= 0.08 A$

5 0

3 years ago

The distance between the ruled lines on a diffraction grating is 1900 nm. The grating is illuminated at normal incidence with a

SashulF [63]

Answer:

3.28 degree

Explanation:

We are given that

Distance between the ruled lines on a diffraction grating, d=1900nm= $1900\times 10^{-9}m$

Where $1nm=10^{-9} m$

$\lambda_2=400nm=400\times10^{-9}m$

$\lambda_1=700nm=700\times 10^{-9}m$

We have to find the angular width of the gap between the first order spectrum and the second order spectrum.

We know that

$\theta=sin^{-1}(\frac{m\lambda}{d})$

Using the formula

m=1

$\theta_1=sin^{-1}(\frac{1\times700\times 10^{-9}}{1900\times 10^{-9}})$

$\theta=21.62^{\circ}$

Now, m=2

$\theta_2=sin^{-1}(\frac{2\times400\times 10^{-9}}{1900\times 10^{-9}})$

$\theta_2=24.90^{\circ}$

$\Delta \theta=\theta_2-\theta_1$

$\Delta \theta=24.90-21.62$

$\Delta \theta=3.28^{\circ}$

Hence, the angular width of the gap between the first order spectrum and the second order spectrum=3.28 degree

6 0

3 years ago

Record the lengths of the sides of ABC and ADE.

ivann1987 [24]

Can you show the rest of the problem

6 0

3 years ago

Write down the principal of lever

pashok25 [27]

Answer:

See the explanation below.

Explanation:

A lever is a simple machine that changes the magnitude and direction of the force applied to move an object. Minimizes the force needed to lift the object.

By means of the following image, we can see the principle of operation of a lever.

The load can be moved thanks to the force multiplied by the distance to the fulcrum.

3 0

3 years ago

A EXAMPLE OF WHEN BOTH PHYSICAL CHANGE AND CHEMICAL CHANGE OCCUR 3 EXAMPLES

kvasek [131]

Answer:

I know 1, that is in the case of a burning of a candle.

Explanation:

5 0

3 years ago