Answer: For the scientist to have alternative hypothesis considered, it is imperative he takes certain steps, this steps will ascertain the scientific claims already made about the evolution of species.
Therefore,the scientist will simply test the alternative hypotheses inorder to know that they are incorrect.
This testing of hypotheses to ascertain their incorrectness is very useful in the study of fossils.
I think the answer for this Question is DNA
Answer:
The answers to the blank spaces are numbered as follows:
1. Function
2. Nucleus
3. Mitochondria
4. ATP
5. Chloroplast
6. Glucose
7. Ribosomes
Explanation:
This question is describing the organelles found in a cell. An organelle is a structure that performs a specific FUNCTION (1) in a cell. There are different kinds of organelles with each possessing its own peculiar function. Some of them are as follows:
- NUCLEUS, which is regarded as the brain of a cell because it directs or controls a cell's activities just like the brain of an organism does.
- MITOCHONDRIA is an organelle that produces the energy storing compound called ATP (adenosine triphosphate), hence, it is called power house of the cell.
- CHLOROPLAST is an organelle found in plant cells that functions in the conversion of light energy (from sun) into GLUCOSE (chemical energy) in a process called PHOTOSYNTHESIS.
- RIBOSOMES is an organelle found in both prokaryotic and eukaryotic cells that serves as the site of PROTEIN production in a cell.
Answer:
120 gramos de CO₂
Explanation:
La ecuación química balanceada para la reacción de combustión del hidrocarburo C₃H₈ (propano) es la siguiente:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Por lo tanto, 1 mol de C₃H₈ produce 3 moles de CO₂. Ahora debemos convertir las moles a gramos utilizando el peso molecular (PM) de cada compuesto:
PM(C₃H₈)= (3 x 12 g/mol) + (8 x 1 g/mol) = 44 g/mol
1 mol C₃H₈ = 1 mol x 44 g/mol = 44 g
PM(CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol
3 mol CO₂ = 3 mol x 44 g/mol = 132 g
Por lo tanto, se producen 132 gramos de CO₂ a partir de 44 gramos de C₃H₈ y la relación estequiométrica es:
3 mol CO₂/1 mol C₃H₈ = 132 g CO₂/44 g C₃H₈
Finalmente, para calcular cuántos gramos de CO₂ se producen al quemar 40 g de C₃H₈, multiplicamos la relación estequiométrica por la masa a quemar:
masa CO₂ producida = 40 g C₃H₈ x 132 g CO₂/44 g C₃H₈= 120 g
