So long as the perimeters are the same, rectangles and squares share the same area. For example, a square that is 2m by 2m across is 4m squared. A rectangle of 4m by 1m across is still 4m squared.
Therefore all we want to do here is see how big we can make our “square” perimeter using the creek. We have three sides to spread 580ft across, therefore if we divide this by 3, we get 193.3ft of fencing per side. If we then square this figure, we will then get the maximum possible area, which comes to 37,377ft squared. (That’s a huge garden).
Mean 87.5
Median 88
Range 14
and Mode All values appeared just once
If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16.
44.2%= 287
Let the total attempt = x
(287/x) ×100 = 44.2
287/x = 44.2/100
287/x = 0.442
x = 287/0.442
<h3>x= <u>649 </u></h3>
Hope this will help...
