Answer:
Question 1 Answer : x^2 - 2y^2
Question 2 Answer: x^2
- 36
ANSWER
24
EXPLANATION
For a matrix A of order n×n, the cofactor
of element
is defined to be

is the minor of element
equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.
Here, we have

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

Since the determinant of a 2×2 matrix is

it follows that

so 
<span>Length = l</span>
<span>
Width = w</span>
<span>
Perimeter = p = 100
</span>
<span>Perimeter of rectangle = 2(l+w)</span>
<span>
100 = 2 (4w + w)</span>
<span>
100 = 2(5w)</span>
<span>
100 = 10w</span>
<span>
100/10 = w</span>
<span>
10 = w</span>
<span>
w = 10
Area of rectangle = length * width</span>
<span>
a = l*w</span>
<span>
a = 4w*w</span>
<span>
a = 4w^2............(1)</span>
<span>
Put the value of w in (1)</span>
<span>
a = 4(10)^2</span>
<span>
a= 4(100)</span>
<span>
a = 400 yd^2</span>
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
- Is y = 4x - 7 a linear function?
- Is y = 6x² - 1 a linear function?
- Is y =
+ 10 a linear function?
Step-by-step explanation:
- Yes it is - when you graph this equation, it results in a [straight] line, signalling that it is a linear function.
- No it's not - when you graph this equation, it results in a v- kinda shape on the graph. Linear functions are [straight] lines on a graph, and this line wasn't straight. In fact, this wasn't even a line.
- No it's not - when you graph this equation, it results in a bend at the origin. The line on the graph is not straight, so this is not a linear equation.
For the graphs -
- The first one represents the linear function [y = 4x - 7]
- The second one (that looks like an L) represents the last not linear function [y =
+ 10]
- The third one (that looks like a V) represents the first not linear function [y = 6x² - 1]
I HOPE THIS HELPS!
Answer:
Step-by-step explanation:
∠DEF=90-58.2=31.8°