Answer:
2 triangles are possible.
Step-by-step explanation:
Given
a=6
b=10
A=33°
To find:
Number of triangles possible ?
Solution:
First of all, let us use the <em>sine rule</em>:
As per Sine Rule:

And let us find the angle B.

This value is in the 1st quadrant i.e. acute angle.
One more value for B is possible in the 2nd quadrant i.e. obtuse angle which is: 180 - 65.44 = 
For the value of
, let us find
:

Let us find side c using sine rule again:

So, one possible triangle is:
a = 6, b = 10, c = 10.89
A=33°,
A=65.44°,
C=81.56°
For the value of 
, let us find
:

Let us find side c using sine rule again:

So, second possible triangle is:
a = 6, b = 10, c = 5.91
A=33°,
A=114.56°,
C=32.44°
So, answer is : 2 triangles are possible.