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4 years ago

I really need help right now I'm stuck on this one

Mathematics

1 answer:

fomenos4 years ago

5 0

I think it is b. No, the chances of getting eight correct by guessing is very low.

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What is 3/4 h = – 45/52

sergiy2304 [10]

Mixed number form: h = - 1 2/13 Hope that helps :))

6 0

3 years ago

What is the slope and y-intercept of 6x-5y=13

DaniilM [7]

Answer:

The slope is 6/5 and the y intercept is -13/5

Step-by-step explanation:

6x-5y=13

Solve for y

Subtract 6x from each side

6x-6x-5y=-6x+13

-5y = -6x+13

Divide by -5

-5y/-5 = -6x/-5 +13/-5

y = +6/5x -13/5

This is in slope intercept form y = mx+b where m is the slope and b is the y intercept

The slope is 6/5 and the y intercept is -13/5

5 0

3 years ago

Find the slope of the line from two points (9, 6) (13,11) Use the equation of the line

mafiozo [28]

Answer:

Step-by-step explanation:

4 0

3 years ago

Mike has $72 and he needs to buy some apples. Which of these equations would represent mike's situation of the apples cost $0.60

Alexxandr [17]

Answer:120 apples

Step-by-step explanation:

72/.60=120

8 0

3 years ago

When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w

deff fn [24]

Answer:

A 90% confidence interval for p will be narrower than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - α) % confidence interval for a population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Here $\hat p$ is the sample proportion.

The margin of error of the confidence interval is:

$MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The MOE is dependent on:

Confidence level
Standard deviation
Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of z for 90% confidence level is:

$z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645$

And the critical value of z for 99% confidence level is:

$z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96$

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for p will be narrower than the 99% confidence interval.

6 0

3 years ago