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brilliants [131]
3 years ago
13

A baseball team had $1,000 to spend on supplies. The team spent $185 on a new bat. New baseball cost $4 each. The inequality 185

+4b≤1,000 can be used to determine the number of new baseball, b, that the team can purchase. Which statement about the number of new baseballs that can be purchased is true?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

This question is incomplete

Complete Question

A baseball team had $1,000 to spend on supplies. The team spent $185 on a new bat. New baseballs cost $4 each.

The inequality 185 + 4b ≤ 1,000 can be used to determine the number of new baseballs (b) that the team can

purchase. Which statement about the number of new baseballs that can be purchased is true?

A. The team can purchase 204 new baseballs.

B. The minimum number of new baseballs that can be purchased is 185.

C. The maximum number of new baseballs that can be purchased is 185.

D. The team can purchase 185 new baseballs, but this number is neither the

maximum nor the minimum.

Answer:

D. The team can purchase 185 new baseballs, but this number is neither the maximum nor the minimum.

Step-by-step explanation:

The first step would be to solve the given equation:

185 + 4b ≤ 1000

4b ≤ 1000 - 185

4b ≤ 815

Divide both sides by 4

b ≤ 203.75

The maximum amount of baseballs the team can buy is 203. This means that they can buy 203 or less than that amount.

Of all the options give, option D is the correct option because the team can purchase 185 new baseballs, but this number is neither the maximum nor the minimum.

The maximum number of ball they can buy is 203 balls and the minimum is zero.

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In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi
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Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n  = 50

sample mean \overline x = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

X \sim N ( \mu \sigma)

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})

P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})

P(X>140) = 1 - P( Z\leq0.42)

From z tables,

P(X>140) = 1 - 0.6628

P(X>140) = 0.3372

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

Y \sim Binomial (np)

Y \sim Binomial (50,0.3372)

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49}  + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +...  + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}

P(Y ≥ 15) = 0.763

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Answer:

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Step-by-step explanation:

Given that:

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1. Undeliverable Mail Pieces. Of the 155 billion mailpieces the U.S. Postal Service (USPS) processed and delivered in 2017, 4.3%
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Answer:

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