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kow [346]
2 years ago
10

Explain how you could find the measurements of an enlargement if you know the ratio of the measurements of the original to the m

easurements of the enlargement.
answer FASTTT
Mathematics
1 answer:
lord [1]2 years ago
4 0

Answer:

showing bellow

Step-by-step explanation:

Let me use an exsample to show this.

Nash is making a framed enlargement of a Mary Cassatt postage stamp to present to a retired postmaster. He enlarges the stamp using a scale of 2 inches to 1 centimeter. If the actual length of the stamp is 3 centimeters and its width is 5 centimeters, what are the dimensions of the scale picture?

6 inches by 10 inches

Step-by-step explanation:

It tells us that the scale is 2 In: 1 cm so we know that for every centimeter long or wide the stamp is the enlardged scale is two inches.

2 times 3 is 6. 6 inches. we are multiplying two inches by the number of centimeter long it is.

5 times 2 is 10 inches. we are multiplying two inches by the number of centimeter wide it is.

therefore the enlarged stamp is 6 In by 10 In.

Hope this helps :)

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Describe how the graph is related to the graph of y = lxl.
Crazy boy [7]

Answer:

Vertical shift down 4 units

Step-by-step explanation:

Vertical shift down 4 units

8 0
3 years ago
WILL MARK YOU BRAINLIEST
Anna007 [38]

rhoumbus that is what I use and got right!!

Step-by-step explanation:

5 0
3 years ago
A rectangular field on a farm is to be fenced in using the wall of the barn for one side and 200 meters of fencing for the other
vitfil [10]

Answer:

Rectangular area as a function of x :   A(x)  = 200*x  + 2*x²

A(max) = 5000 m²

Dimensions:

x = 50 m

l  = 100 m

Step-by-step explanation:

"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:

A(r) = x* l     and the perimeter of the rectangular shape is

P = 2*x + 2*l   but we won´t use any fencing material along the wll of the barn therefore

P  =  2*x + l       ⇒   200 = 2*x  + l      ⇒   l  = 200 - 2*x      (1)

And the rectangular area as a function of x is:

A(x)  = x * ( 200 - 2*x)  ⇒  A(x)  = 200*x  + 2*x²

Taking derivatives on both sides of the equation we get:

A´(x)  =  200 - 4*x     ⇒   A´= 0

Then    200 - 4*x  = 0     ⇒   4*x =  200   ⇒  x  = 50 m

We find the l value, plugging the value of x in equation (1)

l  = 200 - 2*x     ⇒ l = 200 - 2*50   ⇒  l = 100  m

A(max)  =  100*50

A(max)  = 5000 m²

3 0
3 years ago
Example 2:
Montano1993 [528]
Taking this example into account, we can see that setting the first value equal to 1, we obtain that F(x)=0.5x+1=4 and x=6. Using this information, we find that F(x+1)=0.5(x+1)+1=0.5(6+1)+1=4.5. It shows that when x is positive, the succussive terms are increasing.

Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that F(x)=0.5x+1=-19 and x=-40. In the next iteration, F(x+1)=0.5(x+1)+1=0.5(1-40)+1=-18.5. In the next iteration, F(x+2)=0.5(x+2)+1=0.5(2-40)+1=-18. By this way, we find that even if the initial value is less than zero, value of the successive iterations is increasing. 

Using the function g(x)=-x+2 and taking the initial value equal to 4, we find that g(x)=-x+2=4 and x=-2. In the next iteration, g(x+1)=-(x+1)+2=-(-2+1)+2=3. If we continue the iterations we'll see that they are decreasing.
Setting the initial value equal to 2, we find that g(x)=-x+2=2 and x=0. The next iteration is g(x+1)=-(x+1)+2=1. In this case, the interations are also decreasing. 
If we set the initial value equal to 1, we find that g(x)=-x+2=1 and x=1. In the next iteration, g(x+1)=-(x+1)+2=0 and the iterations are decreasing. 
8 0
3 years ago
Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1 2 inches long. The scale
Vlad1618 [11]
Your answer is 14 :) 
8 0
3 years ago
Read 2 more answers
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