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babunello [35]
3 years ago
7

Use m for the number of monkeys and e for the number of elephants. In a zoo, there are 5 times as many monkeys as there are elep

hants. How many monkeys are there?
Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
Well I would guess there are 5 times as many monkeys? I need more details and also just take it like this if there are 2 elephants theres 10 monkeys 3 elephants 15 monkeys.
mixer [17]3 years ago
4 0
M=5e
This is unanswerable because you cannot solve when there are 2 variables.
You might be interested in
-9q = 63 what would be q
Snezhnost [94]

Answer:

-7

Step-by-step explanation:

-9q = 63

q= 63/-9 = -7

7 0
3 years ago
On the last day of school, Mrs. Awesome gave jelly beans to her class. She gave each boy as many jelly beans as there were boys
professor190 [17]

Answer:

28 students

Step-by-step explanation:

Let x be the number of girls in the class. There were two more boys than girls in her class, then the number of boys is x + 2.

Mrs. Awesome gave each boy as many jelly beans as there were boys in the class, so each of x + 2 boys got x + 2 jelly beans, so

Number of boys = x + 2

Number of jelly beans each boy got = x + 2

Total number of jelly beans all boys got = (x + 2)(x + 2)

Mrs. Awesome gave each girl as many jelly beans as there were girls in the class, so each of x girls got x jelly beans, so

Number of girls = x

Number of jelly beans each girl got = x

Total number of jelly beans all girls got = (x)(x)

Hence,

Total number of jelly beans class got = (x + 2)(x + 2) + (x)(x)

Mrs. Awesome brought 400 jelly beans, and when she finished, she had six jelly beans left, so she gave 400 - 6 = 394 jelly beans to the calss.

So,

(x+2)(x+2)+(x)(x)=394\\ \\x^2+2x+2x+4+x^2=394\\ \\2x^2+4x+4-394=0\\ \\2x^2+4x-390=0\\ \\x^2+2x-195=0\\ \\D=2^2-4\cdot (-195)=4+780=784\\ \\\sqrt{D}=28\\ \\x_{1,2}=\dfrac{-2\pm 28}{2\cdot 1}=-15,\ 13

Number of girls cannot be negative, so x = 13, x + 2 = 15 and total number of students is 13 + 15 = 28

3 0
3 years ago
Compare the average rate of change for both functions over the interval [0,3].
Verizon [17]
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.

H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
5 0
3 years ago
Five different books (A, B, C, D and E) are to be arranged on a shelf. Books C and D are to be arranged first and second startin
vekshin1
Your answer would be B.
HOPE THIS HELPS YOU! ^_^
5 0
3 years ago
15=5x+45<br><br> What is the value of x?
nordsb [41]

15 = 5x + 45

15 - 45 = 5x

-30 = 5x

-30/5 = x

-6 = x

7 0
2 years ago
Read 2 more answers
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