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astraxan [27]
3 years ago
8

Which could be the first step and simplifying this expression? Check all that apply.

Mathematics
1 answer:
Triss [41]3 years ago
7 0

\bf \left( x^3x^{-6} \right)^2\implies \left( x^{3-6} \right)^2\implies \stackrel{1st~Step}{\left( x^{-3} \right)^2}\implies x^{-6}\implies \cfrac{1}{x^6}\\ \qquad \Downarrow\\ \stackrel{\textit{distributing the exponent}}{\left( x^{3\cdot 2}x^{-6\cdot 2} \right)}\\ \qquad \Downarrow\\ \stackrel{1st~Step}{x^6x^{-12}}\\ \qquad \Downarrow\\ x^{6-12}\\ \qquad \Downarrow\\ x^{-6}\\ \qquad \Downarrow\\ \cfrac{1}{x^6}

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3 years ago
What is the y-intercept of the function y= -1/2cos(3/2x)
Flauer [41]

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Step-by-step explanation:

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5 0
3 years ago
The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large
Maurinko [17]
The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>

Now, let's calculate area for side = 6
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area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>

<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9

So, the area would be 9 times larger.

ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation.  So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.


5 0
3 years ago
Ratio of two complementary angles is 3:7. What's the measures of both angles
Advocard [28]
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3 0
3 years ago
Write a polynomial of least degree with rational coefficients, a leading coefficient of 1, and zeros at 3 and sqr root 7. Expand
Tresset [83]

Answer:

(x-3)(x^2-7) = x^3 -3x^2 -7x + 21

just change the sign of the root and put x in front of it, then multiply the factors all together

(x-3)(x-sqr7)(x+sqr7)    roots come in conjugate pairs to eliminate irrational coefficients

(x-sqr7)(x+sqr7) = x^2-7.  similar to (a-b)(a+b) = a^2-b^2

Step-by-step explanation:

6 0
3 years ago
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