The height of a golfball hit off a 128-foot hill is modeled by the function h(t) = −16t2 + 32t + 128, where h is height in feet
and t is time in seconds. Find the time the golf ball takes to reach the ground.
1 answer:
The time taken for the golf ball to reach the ground is 1 s.
<h3>
Motion of the golf ball</h3>
The path of motion of the golf ball can be described as parabolic because it is projectile.
When the golf ball reaches the ground, the final velocity will be zero.
Velocity of the golf ball is change in height with time.
v = dh/dt
h(t) = -16t² + 32t + 128
dh/dt = -32t + 32
0 = -32t + 32
32t = 32
t = 1 s
Thus, the time taken for the golf ball to reach the ground is 1 s.
Learn more about time of motion here: brainly.com/question/2364404
You might be interested in
Answer:
Step-by-step explanation:
From the initial condition,
So we have that 
Answer:
Option 3 is correct that is
Ask google because I’m so dumb I can’t even read this ! Have a great day I hope you find your answer
9h + 15 > 55
- 15 - 15
9h > 40
h > 40/9
h > 4.44444.
any number greater than 4.44444
Answer:
a. max. 25c. min.13c
b. 2:00
Step-by-step explanation:
