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san4es73 [151]
3 years ago
8

BRAINIEST TO THE ONE WHO ANSWER THIS

Chemistry
2 answers:
maria [59]3 years ago
8 0

Answer:

1. Across a period , the ionization energy increases  because the formation of a cation becomes more difficult owing to the increase in nuclear charge.

2. Ionization energy decreases down the group because the outer electrons become progressively separated from the nucleus and so are less tightly held .

Explanation:

alexandr1967 [171]3 years ago
4 0

Answer:

The statement that best describes the trend in first ionization enery of elements on the periodic table is:

It generally decreases down a group because valence electrons are farther from the nucleus.

The first ionization energy measures how difficult is to release an electron from the outermost shell. The higher the ionization energy the more difficult it is to release an electron, the lower the ionication energy the easier to release an electron.

As the atomic number of the atom increases (which is what happens  when you go down a group) the furthest the outermost shell of electrons will be (the size of the atoms increases) and so those electrons require less energy to be released, which means that the ionization energy decreases.

Hope it helps!

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your answer would be C.

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The molality of a solution that is made by dissolving a certain mass of benzene in 20.6g of carbon tetrachloride is 0.529m. How
antiseptic1488 [7]
Molality of solution = 0.529 m

mass solvent in kg = 20.6 g => 20.6 / 1000 => 0.0206 kg

number of moles = molality x mass solvent

= 0.529 x 0.0206 => <span> 0.0108 mol benzene 
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How many electrons will a fluorine (f) atom gain or lose in forming an ion?
777dan777 [17]
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Drag each tile to the correct location on the image.
nikdorinn [45]

Answer:

[He]: 2s² 2p⁵.

[Ne]: 3s².

[Ar]: 4s² 3d¹⁰ 4p².

[Kr]: 5s² 4d¹⁰ 5p⁵.

[Xe]: 6s² 4f¹⁴ 5d¹⁰ 6p².

Explanation:

  • Noble elements are used as blocks in writing the electronic configuration of other elements as they are stable elements.

  • [He]:

He contains 2 electrons fill 1s (1s²).

So, [He] can be written before the electronic configuration of 2s² 2p⁵.

  • [Ne]:

Ne contains 10 electrons fill (1s² 2s² 2p⁶).

So, [Ne] can be written before the electronic configuration of 3s².

  • [Ar]:

Ar contains 18 electrons is configured as ([Ne] 3s² 3p⁶).

So, [Ar] can be written before the electronic configuration of 4s² 3d¹⁰ 4p².

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Kr contains 36 electrons is configured as ([Ar] 4s² 3d¹⁰ 4p⁶).

So, [Kr] can be written before the electronic configuration of 5s² 4d¹⁰ 5p⁵.

  • [Xe]:

Xe contains 54 electrons is configured as ([Kr] 5s² 4d¹⁰ 5p⁶).

So, [Xe] can be written before the electronic configuration of 6s² 4f¹⁴ 5d¹⁰ 6p².

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Sergio [31]
207 is the mass number. 82 would be the atomic number
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