Answer:
The gases and particles of earths atmosphere scatter sunlight in different directions making the sky a specific color. Since blue light travels shorter, smaller waves its scattered more than others.
At STP 32 g of O₂ would occupy by the same volume as 4 g of He
<h3>Further explanation</h3>
Complete question
At STP 32 g of O₂ would occupy by the same volume as:
- 4.0 g of He
- 8.0 g of CH₄
- 64 g of H₂
- 32 g of SO₂
Standard Conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So the gas will have the same volume if the number of moles is the same
mol of 32 grams of O₂ :
<em>So mol of 4 g He = mol of 32 g O₂</em>
It's B Covalent.Now I'll add more words since the thing says I need to write at least 20 characters.
1a) anion and S-2
1b) cation and Al+3
1c) anion and N-3
1d) cation and Ca+2
First, we write the balanced equation for this reaction:
2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂
From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:
Moles = volume (in L) * molarity
We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:
M₁V₁ = 2M₂V₂
V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L
The volume required is 173.6 mL
