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kari74 [83]
3 years ago
15

In general what two classes of materials dissolve in water

Chemistry
1 answer:
Ivenika [448]3 years ago
3 0
<span>Polar covalent & Ionic are the two materials

</span>
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2. What is the average height in cm for plants in group 2? * 38 cm 56 cm 97 cm 114 cm
Nina [5.8K]

Answer:

76.25cm

Explanation:

38cm + 56cm +97cm +114cm = 305cm

305cm÷4 = 76.25cm

6 0
3 years ago
Planetesimals are made from <br><br> A. Rock<br><br> B. Gas<br><br> C. Stars<br><br> D. Clouds
White raven [17]
A )rock is correct answer
3 0
3 years ago
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A great white shark has resided at a depth where the pressure is 16 atm. If the initial volume of its swim bladder is 4 L, what
padilas [110]

Answer:

The new volume of the gas is 32L

Explanation:

P1 = 16atm

V1 = 4L

P2 = atm

V2 = ?

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (16 * 4) / 2

V2 = 64 / 2

V2 = 32L

The new volume of the gas is 32L

6 0
3 years ago
HELPPP<br>yall please help my sister won't help me ​
ira [324]

\text{H}_3\text{PO}_4  + 3\text{KOH}  \longrightarrow \text{K}_3 \text{PO}_4     +3\text{H}_2 \text{O}\\\\10\text{Na} +2 \text{NaNO}_3  \longrightarrow 6\text{Na}_2 \text{O} + \text{N}_2\\\\\  2\text{H}_3 \text{PO}_4 + 3\text{Mg(OH)}_2 \longrightarrow \text{Mg}_3(\text{PO}_4)_2+6\text{H}_2 \text{O}\\\\2\text{Al(OH)}_3 + 3\text{H}_2 \text{CO}_3 \longrightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{H}_2 \text{O} \\\\2\text{C}_6\text{H}_6+15\text{O}_2 \longrightarrow 12\text{CO}_2 +6\text{H}_2 \text{O}\\

\text{Pb(OH)}_2 +2\text{HCl} \longrightarrow \text{PbCl}_2 +2 \text{H}_2 \text{O}

2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3

3 0
2 years ago
The solubility product for barium sulfate is 1.1 × 10–10. calculate the molar solubility of barium sulfate.
Triss [41]
When it comes to equilibrium reactions in chemistry, there are a lot of equilibrium constants that can be used. In the case of solubility, the appropriate one to use is the equilibrium constant of solubility product denotes as Ksp. This is the concentration of products raised to their coefficients. For example,

 cC ⇔ aA + bB 

Ksp = {[A^a][B^b]}

Now, for the this problem, the reaction is

BaSO₄ ⇔ Ba²⁺ + SO₄²⁻

The reaction is already balanced. Since we don't know the value of Ba²⁺ and SO₄²⁻, let's denote this at x.

1.1 × 10⁻¹⁰ = [x][x] =[x²]
[x] = [Ba²⁺] = [SO₄²⁻] = [BaSO₄] = 1.049 × 10⁻⁵ M
8 0
3 years ago
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