Hello,

$u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \ r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \ a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\

$

8 0

4 years ago

Read 2 more answers

PLEASE HELP ANSWER ASAP

Solnce55 [7]

I cant help you on this if there is no coefficients.

3 0

3 years ago

Write a function that represents the profit P for selling c cups of hot chocolate

Mars2501 [29]

Sorry don’t know this one

3 0

3 years ago

Use the number line below, where RS = 8y +4, ST = 4y + 7, and RT = 107.

NISA [10]

Answer:

a) Finding value of y:

8y+4+4y+7=107

12y+11=107

12y =107-11

12y =96

y = 96/12

y = 8

b) RS= 8y+4

= 8(8)+4

= 64+4

= 68

ST= 4y+7

= 4(8)+7

= 32+7

= 39

8 0

3 years ago