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Simora [160]
2 years ago
9

Plz answer ASAP thanks

Mathematics
1 answer:
Nana76 [90]2 years ago
6 0
A = 1/2(8)(10) + 1/2(6)(8)
A = 40 + 24
A = 64

answer
64 in^2
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A police officer is chasing a purse-snatcher down a street. The thief starts 9 meters ahead of the officer and can run 20 meters
lions [1.4K]

Answer:

If you want them at the same exact point then since the theif is 9 steps ahead it

will take 3 seconds

Step-by-step explanation:

Robber:

<em>starts at 9</em>

<em>starts at 9add on 5 and you get 14</em>

<em>starts at 9add on 5 and you get 14add 5 more you get 19</em>

<em>starts at 9add on 5 and you get 14add 5 more you get 19and another 5 would give you 24</em>

Police:

<em>is</em><em> </em><em>at</em><em> </em><em>0</em><em> </em><em>meters</em><em> </em>

<em>add</em><em> </em><em>8</em><em> </em><em>any</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>8</em>

<em>add</em><em> </em><em>8</em><em> </em><em>more</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>1</em><em>6</em>

<em>and</em><em> </em><em>another</em><em> </em><em>8</em><em> </em><em>would</em><em> </em><em>get</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>2</em><em>4</em>

6 0
3 years ago
F:[1/2,infinity)—&gt;[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain
dexar [7]

Answer:

f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

\pm \sqrt{y-3/4}=x-1/2

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

\sqrt{y-3/4}=x-1/2

Add 1/2 on both sides:

1/2+\sqrt{y-3/4}=x

The last step is to switch x and y:

1/2+\sqrt{x-3/4}=y

y=1/2+\sqrt{x-3/4}

f^{-1}(x)=1/2+\sqrt{x-3/4}

8 0
2 years ago
At the yard sale,3\4 of items for sale were toys and 5\6 of the items for sale were books Were there more toys of books for sale
Vesnalui [34]

Answer:

No, the books had more sales by 5/6 being bigger (Greater Than) than 3/4.

5 0
3 years ago
A set of 3 consecutive integers has a sum of 15. Which integers are they?
ludmilkaskok [199]

The answer is 4+5+6=15.Hope that helps. :)

5 0
2 years ago
Read 2 more answers
Please answer question three and four if you can :)<br> Show full working out ty;)
nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0
3 years ago
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