Answer:
2
3
5
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Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
Step-by-step explanation:
THE TRICK HERE IS TO DISTRIBUTE THE MINUS SIGN TO THE SECOND TERM.
(6X+5)-(X-3)=
6X+5-X+3 (REMEMBER A NEGATIVE TIMES A NEGATIVE EQUALS A POSITIVE)
NOW COMBINE LIKE TERMS.
5X+8
Answer:
To solve for x the equation would be. (120 - 48) ÷ 2 = X
Step-by-step explanation:
This is because to follow pemdas you do the parenthesis first so you subtract both of the shorter sides. Next since there are two longer sides you divide by two to get the answer. Each longer side is equal to 36 inches.
Hope this helps
Answer:
AE = 19 and <EDC = 59
Step-by-step explanation:
i am almost positive that those are both right
