All categories

3 years ago

I just really need to finish this math stuff so plz help me

Mathematics

2 answers:

ddd [48]3 years ago

8 0

Answer:

$\frac{wx}{5}$

Step-by-step explanation:

Given

$\frac{7wxy}{35y}$

Cancel y on numerator/ denominator and 7/ 35 by 7, leaving

$\frac{xx}{5}$

andriy [413]3 years ago

4 0

Answer: = 5wx $y{2}$

Step-by-step explanation:

you revers the equation like this

= 35 divided by 7

= 5 then you place the wxy together

You might be interested in

A car travels at a speed of s miles per hour. It covers 126 miles in 3 hours.

makvit [3.9K]

Answer:

s=42

Step-by-step explanation: 126 divided by 3 = 42

42mph

8 0

2 years ago

Given that P = (-4, 11) and Q = (-5, 8), find the component form and magnitude of vector QP

Svetach [21]

The given points are
P = (-4,11)
Q = (-5,8)

The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3

The vector QP is
(1,3) or
$\vec{QP} = \hat{i} + 3\hat{j}$

The magnitude of the vector is
√(1² + 3²) = √(10)

Answer:
$\vec{QP} = \hat{i}+3\hat{j} \,\, or \,\, (1,3)$
The magnitude is √(10).

8 0

3 years ago

Solving systems of equations using any method

andreev551 [17]

Answer:

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 5 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

Answer: {x = 5 , y = 2

7 0

3 years ago

(8x^2+2x-6)-(5^2-3x+2)

FrozenT [24]

The answer to this math equation would be 8x^2+5x-33

4 0

3 years ago

obtain the equation of two points passing of lines 4x-3y-1=0 and 2x-3y+3=0 and equally inclined to the axes

klasskru [66]

Answer:By 8(4)P.5, the slope of the line equally inclined to axes is tan(±45

)=±1. Hence by P+λQ=0,

5λ+3

2λ+4

=±1

⇒λ=

,−1. Putting for λ, the two lines are

x−y=0,x+y−2=0.

Was this answer helpful

8 0

3 years ago