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bija089 [108]
3 years ago
15

What’s the addition expression that has the value of 8

Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

There are a few.

Here are some:

1+7=8

4+4=8

2+2+2+2=8

8+0=8

You might be interested in
Solve the system of linear equations using elimination. −7x + 3y = −6 −3x + 3y = 6
Marysya12 [62]

Answer:

x = 3 , y = 5

Step-by-step explanation:

Solve the following system:

{3 y - 7 x = -6 | (equation 1)

3 y - 3 x = 6 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x) + 3 y = -6 | (equation 1)

0 x+(12 y)/7 = 60/7 | (equation 2)

Multiply equation 2 by 7/12:

{-(7 x) + 3 y = -6 | (equation 1)

0 x+y = 5 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{-(7 x)+0 y = -21 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 3 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

Answer:  {x = 3 , y = 5

8 0
4 years ago
Read 2 more answers
Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = -2x 4 6x 3y =
wariber [46]

The missing value is 12 in a system of equations with infinitely many solutions conditions.

It is given that in the system of equations there are two equations given:

\rm y =n -2x+4\\\rm and \\\rm 6x+3y= ?

It is required to find the missing value in the second equation.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

We have equations:

\rm y = -2x+4 ....(1)\\  \\\rm 6x+3y= ?  ....(2)

Let's suppose the missing value is 'Z'

We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.

From equation (1)

\rm y = -2x+4 \\\\\rm 2x+y=4(multiply both the sides by 3)

\rm 6x+3y=12 ...(3)

By comparing the equation (2) and (3), we get

M = 12

Thus, the missing value is 12 in a system of equations with infinitely many solutions conditions.

Learn more about the linear equation.

brainly.com/question/11897796

8 0
2 years ago
Write the equation of the line that passes through the points (6,2) (4,1)
Alisiya [41]

Answer: y=1/2x-1

Step-by-step explanation:

To find the equation of the line that passes through the points, we need to find out slope, m.

m=\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

We plug our points into this formula to find slope.

m=\frac{1-2}{4-6} =\frac{-1}{-2} =\frac{1}{2}

Our slope is 1/2. To find our y-intercept, b, we would plug any point into the equation for slope-intercept form.

y=mx+b

y=1/2x+b

1=1/2(4)+b

1=2+b

b=-1

Now that we know b, our equation is y=1/2x-1.

6 0
3 years ago
Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)
Bess [88]

Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

<u><em>5*[∫x^{2}dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>

<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

4 0
3 years ago
What are the coordinates of the roots of the equation x sqaured + 4x + 3= 0
scZoUnD [109]

Answer:

a

x

2

+

b

x

+

c

=

0

the formula for the roots is

x

=

−

b

±

√

b

2

−

4

a

c

2

a

(

1

)

Identify the values for

a

,

b

,

&

c

x

2

+

4

x

+

3

=

0

cmp

a

x

2

+

b

x

+

c

=

0

a

=

1

b

=

4

c

=

3

(

2

)

Substitute these numbers into eh formula

x

=

−

4

±

√

4

2

−

(

4

×

1

×

3

)

2

×

1

(

3

)

Carefully proceed and do the calculations

x

=

−

4

±

√

16

−

12

2

x

=

−

4

±

√

4

2

x

=

−

4

±

2

2

now calculate the two separate solutions

x

1

=

−

4

+

2

2

=

−

2

2

=

−

1

x

2

=

−

4

−

2

2

=

−

6

2

=

−

3

Answer link

Step-by-step explanation:

8 0
2 years ago
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