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Virty [35]
2 years ago
10

Gregory draws a scale drawing of his room. The scale that he uses is 1cm: 4ft. On this drawing, the room is 3cm long. Which equa

tion can be used to find the actual length of Gregory's room?
A. 1/4 = x/3 C. 1/4 = 3/x

B. x/4 = 1/3 D. 1/x = 4/3

Rob chose A as the correct answer. What did he do wrong?
Mathematics
1 answer:
stepladder [879]2 years ago
3 0

<em><u>The equation can be used to find the actual length of Gregory's room is:</u></em>

\frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

<em><u>Solution:</u></em>

Given that,

The scale that he uses is:

1 cm : 4 feet

On this drawing, the room is 3 cm long

Let "x" be the actual length of room

Therefore,

1 cm : 4 feet

3 cm : "x" feet

This forms a proportion. Therefore,

\frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

Therefore, Option C is correct

Given that,

Rob chose A as the correct answer. Which is,

\frac{1}{4} = \frac{x}{3}

But option A is wrong

So, Rob made a mistake in measuring the equivalent ratio, it should be \frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

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Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

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Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

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It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

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f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

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Step-by-step explanation:

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Step-by-step explanation:

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Also, note that the shaded region is above the graph. Since it is above, it means that y is greater than whatever x is.

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5 0
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