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Virty [35]
3 years ago
10

Gregory draws a scale drawing of his room. The scale that he uses is 1cm: 4ft. On this drawing, the room is 3cm long. Which equa

tion can be used to find the actual length of Gregory's room?
A. 1/4 = x/3 C. 1/4 = 3/x

B. x/4 = 1/3 D. 1/x = 4/3

Rob chose A as the correct answer. What did he do wrong?
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

<em><u>The equation can be used to find the actual length of Gregory's room is:</u></em>

\frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

<em><u>Solution:</u></em>

Given that,

The scale that he uses is:

1 cm : 4 feet

On this drawing, the room is 3 cm long

Let "x" be the actual length of room

Therefore,

1 cm : 4 feet

3 cm : "x" feet

This forms a proportion. Therefore,

\frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

Therefore, Option C is correct

Given that,

Rob chose A as the correct answer. Which is,

\frac{1}{4} = \frac{x}{3}

But option A is wrong

So, Rob made a mistake in measuring the equivalent ratio, it should be \frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

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  B. 9πx^6

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given the following functions f(x) and g(x), solve (f g)(3) and select the correct answer below: f(x) = 6x 3 g(x) = x − 7 4 17 2
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A biology class has a total of 35 students. The number of females is 11 less than the number of males. How many males and how ma
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Answer:

23 males and 12 females

Step-by-step explanation:

x = # of females

y = # of males

x + y = 35

x + x + 11 = 35

2x + 11 =35    (SUBTRACT 11 FROM BOTH SIDES)

2x = 24          (DIVIDE BOTH SIDES BY 2)

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Answer:

Null hypothesis:p=0.4  

Alternative hypothesis:p \neq 0.4

z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98  

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Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

\hat p=\frac{81}{144}=0.5625 estimated proportion of  people with type A blood

p_o=0.4 is the value that we want to verify

\alpha=0.01 represent the significance level

z would represent the statistic

p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.:  Null hypothesis:[tex]p=0.4  

Alternative hypothesis:p \neq 0.4  

the statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98  

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

p_v =2*P(z>3.98)=0.0000689  

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

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