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Virty [35]
3 years ago
10

Gregory draws a scale drawing of his room. The scale that he uses is 1cm: 4ft. On this drawing, the room is 3cm long. Which equa

tion can be used to find the actual length of Gregory's room?
A. 1/4 = x/3 C. 1/4 = 3/x

B. x/4 = 1/3 D. 1/x = 4/3

Rob chose A as the correct answer. What did he do wrong?
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

<em><u>The equation can be used to find the actual length of Gregory's room is:</u></em>

\frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

<em><u>Solution:</u></em>

Given that,

The scale that he uses is:

1 cm : 4 feet

On this drawing, the room is 3 cm long

Let "x" be the actual length of room

Therefore,

1 cm : 4 feet

3 cm : "x" feet

This forms a proportion. Therefore,

\frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

Therefore, Option C is correct

Given that,

Rob chose A as the correct answer. Which is,

\frac{1}{4} = \frac{x}{3}

But option A is wrong

So, Rob made a mistake in measuring the equivalent ratio, it should be \frac{1\ cm}{4\ feet } = \frac{3\ cm }{x\ feet }

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Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
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Step-by-step explanation:

The probability density function of an exponential distribution is:

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The value of E (X) is 10.

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\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

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