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ikadub [295]
3 years ago
10

Simplify: Negative two and one-third minus negative ten and one-sixth(20 points)

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

Given:

The expression is

-2\dfrac{1}{3}-\left(-10\dfrac{1}{6}\right)

To find:

The value of the expression.

Solution:

We have,

-2\dfrac{1}{3}-\left(-10\dfrac{1}{6}\right)=-2\dfrac{1}{3}+10\dfrac{1}{6}

Convert the mixed fraction in improper fraction.

=-\dfrac{2\times 3+1}{3}+\dfrac{10\times 6+1}{6}

=-\dfrac{6+1}{3}+\dfrac{60+1}{6}

=-\dfrac{7}{3}+\dfrac{61}{6}

Taking LCM, we get

=\dfrac{-2(7)+61}{6}

=\dfrac{-14+61}{6}

=\dfrac{42}{6}

Convert it into mixed fraction.

=\dfrac{6(7)+5}{6}

=7\dfrac{5}{6}

Therefore, the correct option is C.

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Step-by-step explanation:

Given

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\Rightarrow f'(x)=0.03(10-2x)

At x=1\ f'(x) \ \text{is}

\Rightarrow f'(x=1)=0.03(10-2\times 1)\\\Rightarrow f'(x=1)=0.03(8)\\\Rightarrow f'(x=1)=0.24\ \text{miles per sec}

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2 years ago
The area that lies between Z=-2.61 and Z=0 is
muminat

Answer:

2.61

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0 - (-2.61)       Distribute the negative

0 + 2.61          Add

2.61

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3 years ago
Is the given number a solution of the equation? Which value of c is a solution to the equation c = 2c – 4?
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one yard company charges $50 a month to mow and edge a lawn plus $10 an hour for the worker. A second conpany charges $60 a mont
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3 years ago
) Find the coordinates of the point A' which is the symmetric point
soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point  A(3, 2) with respect to the line 2x + y - 12 = 0.​

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

C( \dfrac{x+3}{2}, \dfrac{y+2}{2})

Also, product of slope will be -1 .( Since, they are parallel )

\dfrac{y-2}{x-3} \times -2  = -1\\\\2y - 4 = x - 3\\\\2y - x = 1

x = 2y - 1

So, C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})

Also, C satisfy given line :

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