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dangina [55]
3 years ago
7

SOMEONE HELP ASAP PLES NO EXPLANATOIN NEEDED PLS LEAVE UR ANSWER AS TEXT (SOME TIMES I CAN'T SEE IMAGES) THANK YOU SO MUCH!!!

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

i cant see the image

Step-by-step explanation:

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A pitchers arm rotates at a speed of 7 degrees per millisecond
Fantom [35]

Answer:

To solve this problem, all we have to do is to use a conversion factor to convert millisecond into seconds. We know that there are 1000 milliseconds in a second, therefore:

pitcher’s arm rotation = 7 degrees / millisecond * (1000 milliseconds / second)

pitcher’s arm rotation = 7,000 degrees / second

Step-by-step explanation:

7 0
4 years ago
Determine whether 8x + 18 + x is equivalent to 9(2+x) Complete the sentence to justify your answer
AlekseyPX

Answer:

Yes they are equivalent

Step-by-step explanation:

8x + 18 + x = 9x + 18

9(2+x) = 18 + 9x = 9x + 18

Therefore, 8x + 18 + x is equivalent to 9(2+x)

6 0
3 years ago
Read 2 more answers
The keyboard of a piano has 88 keys. Generate the equivalent prime factorization of 88.
Verdich [7]

Answer:

11 x 2^3 =11 x 2 x 2 x 2 = 88

Step-by-step explanation:

88

<u>11</u> 8

   <u>2</u> 4

      <u>2</u> <u>2</u>

<u />

Use a factor tree it helps a lot :0).

8 0
3 years ago
0.005 is 1/10 of 0.05 true or false
7nadin3 [17]
False, it would be 0.005 is 5/10 of 0.05. also can you pls answer my question!
7 0
3 years ago
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On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?
bonufazy [111]

Answer:

Birds F_b=14.3\%

Gerbils F_g=42.9\%

Fish F_f=21.4\%

Hamsters F_h=21.4\%

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds  n_b=2

Number of gerbils  n_g=6

Number of fish  n_f=3

Number of hamsters  n_h=3  

Generally the frequency for birds F_b is mathematically given b

F_b=\frac{n_b}{n}*100

F_b=\frac{2}{14}*100

F_b=14.3\%

Generally the frequency for Gerbils F_g is mathematically given b

F_g=\frac{n_g}{n}*100

F_g=\frac{6}{14}*100

F_g=42.9\%

Generally the frequency for fish F_f is mathematically given b

F_f=\frac{n_f}{n}*100

F_f=\frac{3}{14}*100

F_f=21.4\%

Generally the frequency for fish F_h is mathematically given b

F_h=\frac{n_h}{n}*100

F_h=\frac{3}{14}*100

F_h=21.4\%

5 0
3 years ago
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