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EastWind [94]
4 years ago
13

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 2.00 mm away

Physics
1 answer:
Oxana [17]4 years ago
7 0
I have tried to answer this inverse square Coulomb's law question more fully, but have been blocked from doing so. I do not know why.
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Water flows through a garden hose which is attached to a nozzle. The water flows through hose with a speed of 1.81 m/s and throu
Serggg [28]

Answer:

a) 17.086m

b) 0.1671 m

Explanation:

Given data: speed of water through the hose  = 1.81 m/s

through the nozzle = 18.3 m/s

We know that maximum height of an object with upward velocity v is given by,

a) H = v^2/2g

where H is the maximum height water emerges  

= 18.3^2/(2×9.8) = 17.086 m answer

b) Again,  

H = v^2/2g

= 1.81^2/(2×9.8) = 0.1671 m

6 0
3 years ago
A wave travels through a medium because
Amanda [17]

in case you dont want to read the answer is B

5 0
3 years ago
Read 2 more answers
the young’s modulus of aluminum is 69gpa, of nylon is 3gpa, of tungsten is 400gpa, and of copper is 117gpa. if equal-size sample
olga_2 [115]

Answer:

Least to most elongated: tungsten, copper, aluminum, nylon.

Explanation:

Materials with high Young's modulus are difficult to stretch. σ = Yε and ε = ΔL/L so an object with a high Young's modulus (Y) subject to a certain tensile stress (σ) will have a smaller strain than an object with a smaller Young's 's modulus subject to the same tensile stress. If strain (ε) is smaller, then ΔL will also be smaller.

3 0
2 years ago
A brass statue with a mass of 0.40 kg and a density of 8.00×103kg/m3 is suspended from a string. When the statue is completely s
Mars2501 [29]

Answer:

ρ = 1469  kg/m³

Explanation:

given,

mass of statue = 0.4 Kg

density of statue = 8 x 10³ kg/m³

tension in the string = 3.2 N

density of the fluid = ?

Volume of the statue

V = \dfrac{0.4}{8\times 10^3}

V = 5 x 10⁻⁵ m³

W = ρ g V

W = ρ x 9.8 x 5 x 10⁻⁵

now, tension on the string will be equal to

T = mg - W

3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵

ρ x 9.8 x 5 x 10⁻⁵ = 0.72

ρ = 1469  kg/m³

8 0
3 years ago
The annual production of Cl2 is about 45 millions tons per year. Assume that a typical plant is operational 90 % of the year. Th
olga nikolaevna [1]

Answer:

a) CI^-  ⇒ CI2 + 2e^-

b) 4.2 * 10^9  amperes

c) 1.4 * 10^10 watts

Explanation:

Given data:

Annual production of C12 = 45 millions tons per year

Typical plant operational percentage = 90%

Operating voltage of a cell = 3.4 v

A) Half-cell reaction for oxidation chloride to form chlorine

     CI^-  ⇒ CI2 + 2e^-

B) Calculate the total current worldwide needed to generate the global supply of CI 2

Total current = \frac{Q}{t} = \frac{1.2*10^{17} }{2.84*10^7} = 4.2 * 10^9  amperes

Q = charge , t = time

C ) Calculate electrical power need to produce global supply of chlorine using electrolysis

P = V*I

  = 3.4 * 4.2 * 10^9

  = 1.4 * 10^10 watts

7 0
3 years ago
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