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4 years ago

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 2.00 mm away

1 answer:

7 0

I have tried to answer this inverse square Coulomb's law question more fully, but have been blocked from doing so. I do not know why.

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Suppose a door is 1 meter wide. Calculate the difference in the amount torque exerted on the door when someone pushes with a con

Yanka [14]

Answer:

Δτ = 50 N.m

Explanation:

The torque applied on an object is given by the product of the force applied on it and the perpendicular distance between the force and the axis of rotation of the object. That is:

τ = F r

where,

τ = Torque applied on the object

F = Force applied on it

r = distance from axis of rotation

FOR HANDLE SIDE OF DOOR:

τ₁ = F r₁

where,

τ₁ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₁ = distance from axis of rotation = 1 m

Therefore,

τ₁ = (100 N)(1 m)

τ₁ = 100 N.m

FOR MIDDLE OF DOOR:

τ₂ = F r₂

where,

τ₂ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₂ = distance from axis of rotation = 1 m/2 = 0.5 m

Therefore,

τ₂ = (100 N)(0.5 m)

τ₂ = 50 N.m

Now, the difference between the amount of torque in both cases is:

Δτ = τ₁ - τ₂

Δτ = 100 N.m - 50 N.m

Δτ = 50 N.m

6 0

3 years ago

A hammer taps on the end of a 4.10-m-long metal bar at room temperature. A microphone at the other end of the bar picks up two p

xz_007 [3.2K]

Answer:

Speed of sound inside metal is ≅ 8200 $\frac{m}{s}$

Explanation:

Given :

Length of metal bar $x = 4.10$ m

From general velocity equation,

$v = \frac{x}{t}$

Where $v =$ speed of sound in air = 343 $\frac{m}{s}$

For finding time from above equation,

$t = \frac{x}{v}$

$t = \frac{4}{343}$

$t = 0.01166$ sec

Since pulses are separated by $t_{o} =$ $11.1 \times 10^{-3} = 0.0111$ sec

So we take time difference,

$\Delta t = t_{} -t_{o} = 0.0005$

So speed of sound in metal is,

$v = \frac{x}{\Delta t }$

$v = \frac{4.10}{0.0005}$

$v = 8200$ $\frac{m}{s}$

4 0

3 years ago

Your fitness tracker tells you that you have delivered 124 kJ of work during your workout. The tracker also shows that you have

REY [17]

To solve this problem, we must basically count the total energy lost converting all the values given in the international system.

The energy loss is given by both 124KJ and 124food heats.

Since the energy conversion we know that 1 food calories is equal to 4,184J. So:

$124 calories (\frac{4.184J}{1 calories}) = 518.816J = 0.518816kJ$

Therefore the total energy lost will be

$E_{lost} = 124 KJ + 0.518816 KJ$

$E_{lost} = 124.518KJ$

Therefore the total energy lost to the surroindings in form of heat is 124.518kJ

3 0

3 years ago

Car A is traveling at a constant speed vA = 130 km / h at a location where the speed limit is 100 km / h. The police offi cer in

kotykmax [81]

Answer:

Distance = 713.303m

Explanation:

To determine the distance required for the police officer to overtake car A, we simply calculate the time t for which the police car and the speeding car have traveled equal distances from point P

5 0

3 years ago

Read 2 more answers

The energy band gap of GaAs is 1.4eV. calculate the optimum wavelength of light for photovoltaic generation in a GaAs solar cell

Viktor [21]

Answer:

λ = 8.88 x 10⁻⁷ m = 888 nm

Explanation:

The energy band gap is given as:

Energy Gap = E = 1.4 eV

Converting this to Joules (J)

E = (1.4 eV)(1.6 x 10⁻¹⁹ J/1 eV)

E = 2.24 x 10⁻¹⁹ J

The energy required for photovoltaic generation is given as:

E = hc/λ

where,

h = Plank's Constant = 6.63 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light = ?

Therefore,

2.24 x 10⁻¹⁹ J = (6.63 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/λ

λ = (6.63 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.24 x 10⁻¹⁹ J)

λ = 8.88 x 10⁻⁷ m = 888 nm

7 0

3 years ago