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vesna_86 [32]
3 years ago
11

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

Q = c * m * T     where c = specific heat, m = mass, T = temperature change

m = Q / (c * T) = 1000 J / (899 J / kg deg C * 1 deg C)

m = 1000 / 899 kg = 1.11 kg

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4 years ago
(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) —
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Answer:

a)    A = 0.07129 m²

b)    A / A ’= 1.77

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In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

            a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

              l = 0.3302 m

The area of ​​a rectangle is

            A = l a

             A = 0.3302 0.2159

             A = 0.07129 m²

b) we have a second sheet with reduced dimensions

         a ’= 3/4 a

         l ’= ¾ l

Let's find the area of ​​this glossy sheet

         A ’= l’ a ’

         A ’= ¾ l ¾ a

         A ’= 9/16 l a

To find the factor we divide the two quantities

           A / A ’= l a 16 / (9 l a

            A / A ’= 1.77

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