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Simora [160]
3 years ago
8

Write a real world problem that can be modeled by the equation 1.25x=0.75x+50

Mathematics
1 answer:
boyakko [2]3 years ago
4 0
This is not really an equation that can be used to model anything as there is only one variable. see this.
1.25x-0.75x = 50
0.5x = 50
x=100
It can be solved and therefore does not have an input and an output required to model anything
You might be interested in
Help please, question attached
Alexxandr [17]

Answer:

C. x = 8

Step-by-step explanation:

We know that x · x · x is equal to 512. We know it cannot be negative because then the 512 would be negative. -2 x -2 x -2 is -8. -2 x -2 is 4. We know it cannot be B x = -6 or D. x = -8.

Let's multiply 6 x 6 x 6.

                           36 x 6 = 216.

Let's multiply 8 x 8 x 8.

                          64 x 8 = 512

                               

The answer would be C. x = 8.

I hope that this helps! :)

4 0
3 years ago
Read 2 more answers
What is the value of -3 2/3 +1/3
emmainna [20.7K]

Exact Form:

−10/3

Decimal Form:

−3.3...

Mixed Number Form:

−3 1/3

4 0
3 years ago
Read 2 more answers
A group of students are meeting in the cafeteria. 70 students have already arrived. This is 35% of the group. How many are in th
sesenic [268]
There are 200 students in the group.

To find this, you divide 70 by 0.35 (35%). This will give you 200. To check this, multiply 200 by 0.35 and you will get 70. Thus making 200 the answer.

I hope this helps!
4 0
3 years ago
Read 2 more answers
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do
expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) =3x^2 -2x +1

The two basic hypothesis of the mean valued theorem are

  • The function should be continuous in [0,2]
  • The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we  can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

   

4 0
3 years ago
What is .9 to the 50th power?
GaryK [48]
0.9^50=0.0051537752That's your answer.<span>

</span>
8 0
4 years ago
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