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viva [34]
3 years ago
5

You create 15 centerpieces for a party in 5 hours. what is the unit rate?

Mathematics
1 answer:
Tema [17]3 years ago
8 0
15 in 5 hours would mean you are making 3 an hour, or one every 20 minutes.
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Which ordered pair is a solution of the equation?<br> y=4x−7
vampirchik [111]

Answer:

Unknown

Step-by-step explanation:

Hi! so you didn't add the ordered pair options but I will do my best :) so if you see the ordered pair (0.7) that could definitely be a solution because using the slope intercept form equation you gave I know that's our y Intercept. the slope is 4/1 so moving up 4 and to the right 1 or down 4 and to the left 1 on a graph could show you more points! If you don't want to draw it you could use Desmos and just put this equation in or give me the ordered pairs and I will give you your answer!

hope this helps :)

8 0
2 years ago
(3,15) is the solution for what equation
juin [17]
<span>Hello there, i think the answer is 15=3*5
(Please leave a thanks if this IS the right answer! Thanks ;)
What times 3 = 15?
x*3=15
X=5</span>
5 0
3 years ago
Please help me it’s for homwork
notsponge [240]
System b should be (-3,2)!
7 0
3 years ago
A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla
nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = P(A)= \frac{13}{100}=0.13

The probability that athlete is a basketball player = P(B)= \frac{52}{100}=0.52

The probability that athlete is both basket ball player and  football player = P(A\cap B) = \frac{9}{100}=0.09

We have to find the probability that an athlete chosen is either a football player or a basketball player P(A\cup B).

Now we know that;

P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0
4 years ago
The tail on Alex‘s dog is 5 1/4 inches long this link is between which 2 inch marks on a ruler
wlad13 [49]
It's between the 5 and 6
6 0
3 years ago
Read 2 more answers
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