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4 years ago

Ba(oh)2+H3po4+h2o how is it balance ?

Chemistry

1 answer:

Igoryamba4 years ago

4 0

Answer:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Explanation:

Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:

3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O

Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal

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Vanadium v hydroxide formula

Mila [183]

Molecular Formula: H5O5V-5

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3 years ago

Which type of bond shows two or more atoms sharing electrons?

andre [41]

Answer:

Covalent is the type of bond.

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4 years ago

The second-order rate constant for the dimerization of a protein (P) P + P → P2 is 6.2 × 10−3/M · s at 25°C. Part 1 out of 2 If

siniylev [52]

Answer:

$r=1.59\times 10^{-10}\ M/s$

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

From the reaction given that:-

$P+P\rightarrown P_2$

The expression for the rate is:-

$r=k[P]^2$

Given that;- k= $6.2\times 10^{-3}$ /Ms

[P] = $1.6\times 10^{-4}$ M

Thus,

$r=6.2\times \:10^{-3}\times \:\left(1.6\times \:\:10^{-4}\right)^2\ M/s=1.59\times 10^{-10}\ M/s$

8 0

3 years ago

Which of the graphs below might represent a mixture of pure water and ice exposed to a room temperature of 3°C?

Y_Kistochka [10]

Answer:

C. Graph C

Explanation:

We have a mixture of water and ice.

At 0 °C they are at equilibrium.

water-to-ice rate = ice-to-water rate

Next, we lower the temperature to -3 °C — just slightly below freezing.

The water will slowly turn to ice.

The water-to-ice rate will be slightly faster than the ice-to-water rate.

The purple bar will be slightly higher than the blue bar.

Graph C best represents the relative rates

A. is wrong. The ice-to-water rate is faster, so the water is melting. The temperature is slightly above freezing (say, 3 °C).

B. is wrong. The two rates are equal, so the temperature is 0 °C.

D. is wrong. The water-to-ice rate (freezing) is much greater than the ice-to-water rate, so the temperature is well below freezing( say, -10 °C).

6 0

4 years ago

You make two dilutions. You take 83.52 mL of the stock solution and dilute to 500.0 mL to make Solution #1. You then add 52.27 m

kati45 [8]

Answer:

The answer to the question is;

The concentration of the Solution #1 in terms of molarity is

0.16704X moles/litre.

Explanation:

Let the concentration of the stock solution be X moles/liter

Therefore, 83.52 ml of the stock solution contains

83.52×(X/1000) moles

Dilution of 83.52 ml of X to 500 ml gives solution 1 with a concentration of

500 ml of solution 1 contains 83.52×(X/1000) moles

Therefore 1000 ml or 1 litre contains 2×83.52×(X/1000) moles = 0.16704X moles/litre

The molarity of solution 1 is 0.16704X moles/litre.

8 0

4 years ago