Ba(oh)2+H3po4+h2o how is it balance ?

Chemistry

1 answer:

Igoryamba4 years ago

4 0

Answer:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Explanation:

Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:

3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O

Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal

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4 Al + 3O2 → 2Al2O3 If 14.6 grams Al are reacted, how many liters of O2 at STP would be required?

melomori [17]

Answer: 9.08 L

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}$

$\text{Moles of} Al=\frac{14.6g}{27g/mol}=0.54moles$

$4Al+3O_2\rightarrow 2Al_2O_3$

According to stoichiometry :

4 moles of $Al$ require = 3 moles of $O_2$

Thus 0.54 moles of $Al$ will require= $\frac{3}{4}\times 0.54=0.405moles$ of $O_2$

Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 1 atm

V= Volume of the gas = ?

T= Temperature of the gas = 273 K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 0.405

$V=\frac{nRT}{P}=\frac{0.405\times 0.0821\times 273}{1}=9.08L$

Thus 9.08 L of $O_2$ at STP would be required

6 0

3 years ago

Which sample of matter is classified as a solution? 1. H2O(s) 2. H2O(l) 3. CO2(g) 4. CO2(aq)

lys-0071 [83]

Answer : Option 4) $CO_{2}_{(aq)}$

Explanation : $CO_{2}_{(aq)}$ is the only sample of matter which can be classified as a solution. As the solution can be defined as a liquid mixture which contains a minor component (the solute) that is uniformly distributed within the major component (the solvent).

In this case, the solute is $CO_{2}$ which is dissolved in water which acts as an solvent. Also, it has a subscript which is aq. which means aqueous, is often given to the solution in which the solvent is water.