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n200080 [17]
4 years ago
14

Which of the following phase diagrams represents how a catalyst is able to change the rate of a reaction? (2 points) A regular e

xothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with two potential energy hills, instead of the one hill in the regular potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with a taller activation energy hill than that in the original potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with two activation energy hills, the second taller than the first, instead of the one hill in the regular potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.

Chemistry
1 answer:
OverLord2011 [107]4 years ago
7 0

Answer: The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.

Explanation:

Activation energy is the extra amount of energy required by the reactants to cross the energy barrier to get converted into products.

When a catalyst is added, it lowers down the activation energy which is shown by a dotted line. As now less energy is required,  more of reactants can cross the energy barrier and get converted to products and thus increase the rate of reaction.

A catalyst increases the rate of reaction for both exothermic and endothermic reactions.

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The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at
seraphim [82]

Answer:

the solubility of CaCO3 is 0.015g/l 25 °C

is favored at equilibrium

Explanation:

The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at equilibrium?

solubility is the property of a solute to dissolve in a solvent(liquid, gas ) to form a solution(soution can be saturated ,unsaturated, or supersaturated)

CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq)

in partial dissociation , we can say

2.25x 10^-8=Ca^{2+} +CO^{2-}_{3} }

let Ca^2+=CO3^-2=S

2.25x10^-8=S*S

S^2=2.25x10^-8

S=0.00015mol/L

Converting that to g/l

the relative molecular mass of CaCO3=100g/mol

0.00015*100g/mol

0.015g/l

the solubility of CaCO3 is 0.015g/l @room temperature

is favored   at equilibrium

5 0
3 years ago
1. Each substance written to the right of the arrow in a chemical equation is a
Scorpion4ik [409]

Answer: product

Explanation:

Each substance written to the right of the arrow in a chemical equation is referred to as a product.

When writing a chemical equation, the substance that's written to the left of arrow in the equation is the reactants.

On the other hand which is the right side is the product.

5 0
3 years ago
Ethanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuri
Fed [463]

Answer:

a) 88.48%

b) 0.05625 mol

Explanation:

2CH₃CH₂OH(l) → CH₃CH₂OCH₂CH₃(l) + H₂O(g)         Reaction 1

CH₃CH₂OH(l) → CH₂═CH₂(g) + H₂O(g)                        Reaction 2

a) CH₃CH₂OH = 46.0684 g/mol

   CH₃CH₂OCH₂CH₃ = 74.12 g/mol

1 mol CH₃CH₂OH ______  46.0684 g

x                            ______   50.0 g

x = 1.085 mol  CH₃CH₂OH

1 mol  CH₃CH₂OCH₂CH₃ ______  74.12 g g

y                           ______   35.9 g

y = 0.48 mol   CH₃CH₂OCH₂CH₃

100% yield _____ 0.5425 mol CH₃CH₂OCH₂CH₃

w                _____  0.48 mol CH₃CH₂OCH₂CH₃

w = 88.48%

b) Only 0.96 mol of ethanol reacted to form diethyl ether. This means that 0.125 mol of ethanol did not react. 45% of 0.125 mol reacted to form ethylene. Therefore, 0.05625 mol of ethanol reacted by the side reaction (reaction 2). Since 1 mol of ethanol leads to 1 mol of ethylene, 0.05625 mol of ethanol produces 0.05625 mol of ethylene.

4 0
3 years ago
Which gas law states that the pressure of a gas decreases when volume is increased and the temperature is unchanged
Nesterboy [21]

Answer: Boyle's law

Explanation: It states that pressure of a gas is inversely proportional to the volume of a gas at constant temperature.

P∝\frac{1}{V}       at constant temperature

or If the pressure of gas is decreased, the volume increases if the temperature is unchanged and If the pressure of gas is increased, the volume decreases if the temperature is unchanged.

P_1V_1=P_2V_2

3 0
4 years ago
Read 2 more answers
Find the number of moles of barium iodide if you have 5.23 x 1024 formula units of Bal2
Oksi-84 [34.3K]

Answer:

8.68 moles of BaI₂

Explanation:

Given data:

Number of moles of BaI₂ = ?

Number of formula units = 5.23× 10²⁴

Solution:

By using Avogadro number,

1 mole of any  substance contain 6.022× 10²³ formula units.

5.23× 10²⁴ formula units of BaI₂ × 1 mol / 6.022× 10²³ formula units

0.868 × 10¹ moles of BaI₂

8.68 moles of BaI₂

Thus, 5.23× 10²⁴ formula units of BaI₂ contain 8.68 moles of BaI₂

7 0
3 years ago
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