Which of the following phase diagrams represents how a catalyst is able to change the rate of a reaction? (2 points) A regular e
xothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with two potential energy hills, instead of the one hill in the regular potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with a taller activation energy hill than that in the original potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with two activation energy hills, the second taller than the first, instead of the one hill in the regular potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.
Answer: The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.
Explanation:
Activation energy is the extra amount of energy required by the reactants to cross the energy barrier to get converted into products.
When a catalyst is added, it lowers down the activation energy which is shown by a dotted line. As now less energy is required, more of reactants can cross the energy barrier and get converted to products and thus increase the rate of reaction.
A catalyst increases the rate of reaction for both exothermic and endothermic reactions.
<span>Carboxylic acid.
This is because there is no reducing termini. and if one end is a methyl, that is just hydrocarbons, and the rest must also be hydrocarbons. We can assume that there are no other constituents that are making functional groups and given with what we have this is a carboxylic acid.</span>
In order to <span>complete and balance the following reactions, you should add a Fe into it. So it will look like uo2+ +cr o^2- 7 ـــــــــــــــــــــ uo2+ +cr3+Fe. The answer to the following given statement or missing answer is Fe. </span>