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n200080 [17]
4 years ago
14

Which of the following phase diagrams represents how a catalyst is able to change the rate of a reaction? (2 points) A regular e

xothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with two potential energy hills, instead of the one hill in the regular potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with a taller activation energy hill than that in the original potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with two activation energy hills, the second taller than the first, instead of the one hill in the regular potential energy diagram. A regular exothermic potential energy diagram is shown, with a dotted line representing how the potential energy diagram changes with the use of a catalyst. The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.

Chemistry
1 answer:
OverLord2011 [107]4 years ago
7 0

Answer: The dotted line shows a new potential energy diagram with a shorter activation energy hill than that in the original potential energy diagram.

Explanation:

Activation energy is the extra amount of energy required by the reactants to cross the energy barrier to get converted into products.

When a catalyst is added, it lowers down the activation energy which is shown by a dotted line. As now less energy is required,  more of reactants can cross the energy barrier and get converted to products and thus increase the rate of reaction.

A catalyst increases the rate of reaction for both exothermic and endothermic reactions.

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Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −
kicyunya [14]

Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

Mathematically;

ΔH = ΔH(product) - ΔH(reactant)

In the case of the first reaction;

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)  ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca)  = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

Thus;

-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207  KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

For the last reaction;

ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH  of the respective molecules given above,

ΔH  = -1270 + (-393.5) - (-1207)

ΔH  = -456.5 KJ

8 0
3 years ago
Dilution question In many of the experiments, you will be asked to prepare a standard solution by diluting a stock solution. You
riadik2000 [5.3K]

Answer:

We could do two 1:50 dilutions and one 1:4 dilutions.

Explanation:

Hi there!

A solution that is 1000 ug/ ml  (or 1000 mg / l) is 1000 ppm.

Knowing that 1 ppm = 1000 ppb, 100 ppb is 0.1 ppm.

Then, we have to dilute the stock solution (1000 ppm / 0.1 ppm) 10000 times.

We could do two 1:50 dilutions and one 1:4 dilutions (50 · 50 · 4 = 10000). Since the first dilution is 1:50, you will use the smallest quantity of the stock solution (if we use the 10.00 ml flask):

First step (1:50 dilution):

Take 0.2 ml of the stock solution using the third dispenser (20 - 200 ul), and pour it in the 10.00 ml flask. Fill with water to the mark (concentration : 1000 ppm / 50 = 20 ppm).

Step 2 (1:50 dilution):

Take 0.2 ml of the solution made in step 1 and pour it in another 10.00 ml flask. Fill with water to the mark. Concentration 20 ppm/ 50 = 0.4 ppm)

Step 3 (1:4 dilution):

Take 2.5 ml of the solution made in step 3 (using the first dispenser 1 - 5 ml) and pour it in a 10.00 ml flask. Fill with water to the mark. Concentration 0.4 ppm / 4 = 0.1 ppm = 100 ppb.

6 0
3 years ago
In a metal what is not given an assigned location and thus can drift
Allushta [10]
In a metal, "Electrons" <span> is not given an assigned location and thus can drift

In short, Your Answer would be Option C

Hope this helps!</span>
6 0
3 years ago
A mixture is made by combining 1.62 lb of salt and 5.20 lb of water.
WINSTONCH [101]

Answer:

23.8

Explanation:

Formula

weight % = weight of solute/ weight of solution x 100

weight of solution = weight of salt + weight of water

weight of solution = 1.62 lb + 5.20 lb = 6.82 lb

weight % = 1.62 / 6,82 x 100

weight % = 0.238 x 100

weight % = 23.8

4 0
3 years ago
The color of coral depends on ______.
MrRissso [65]

Answer:

Hello I didi this quiz and i got 100% and the answer is (a) hope this helps <3

Explanation:

7 0
2 years ago
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