Consider the following equivalent expressions: 38÷1312 and 38?ab What are the values of a and b? Enter the value of a followed b
y the value of b, separated by a comma.
1 answer:
You might be interested in
Let the acid be HA.
The chemical formula for this acid will be the following:
The formula for the <span>acid dissociation constant will be the following:
</span>![K_a= \dfrac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%20%5Cdfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
<span>
We know [H+]=0.0001 (it's given).
However, we must find [A-] and [HA] in order to solve for the constant.
We find that [A-]=[H+] by using a electroneutrality equation.
Also, we can create a concentration equation to find [HA].
</span>![0.5M=[A^-]+[HA]](https://tex.z-dn.net/?f=0.5M%3D%5BA%5E-%5D%2B%5BHA%5D)
![[HA]=0.5M-[A^-]](https://tex.z-dn.net/?f=%5BHA%5D%3D0.5M-%5BA%5E-%5D)
<span>
Now, we can find the acid dissociation constant.
</span>![K_a= \dfrac{[H^+][A^-]}{0.5M-[A^-]}](https://tex.z-dn.net/?f=K_a%3D%20%5Cdfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B0.5M-%5BA%5E-%5D%7D)
The chemical formula for this acid will be the following:
The formula for the <span>acid dissociation constant will be the following:
</span>
<span>
We know [H+]=0.0001 (it's given).
However, we must find [A-] and [HA] in order to solve for the constant.
We find that [A-]=[H+] by using a electroneutrality equation.
Also, we can create a concentration equation to find [HA].
</span>
<span>
Now, we can find the acid dissociation constant.
</span>