Answer:
P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm
Explanation:
Apply Dalton's Law of Partial Pressures.
P(total) = ∑Partial Pressures = ∑(256mm + 198mm + 48mm) = 504 mmHg
P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm
<span>4 Al + 3 O2 → 2 Al2O3
(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2
0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.
((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =
10.1 g O2 left over</span><span>
</span>
<span>What is the electron configuration of aluminum is </span>1s^2 2s^2 2p^6 3s^2 3p^1.
Explanation:
The graphite anodes are suspended into the brine. During electrolysis, Cl ions are oxidized at the anode and chlorine gas goes out of the cell, while sodium ions are reduced at the mercury cathode forming sodium amalgam. ... Hydrogen gas is obtained as a by–product at the cathode.
