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3 years ago

Rewrite the equation in Ax+By=C Use integers for A, B, and C. y+1=6(x+4)

1 answer:

8 0

So the problem is asking you to write y + 1 = 6(x+4) in the form Ax+By=C. A lot of this will involve algebra and moving the numbers around until you have it in the right form.

1) Start by distributing 6 to x and 4 on the right using the distributive property.
y + 1 = 6(x+4)
y + 1 = 6x + 6(4)
y + 1 = 6x + 24

2) Move everything with the variables x or y onto the left side using addition or subtraction. Move everything else onto the other side. This means subtracting the 6x from both sides and subtracting 1 from both sides. Simplify:
y + 1 = 6x + 24
y - 6x + 1 = 24
y - 6x = 24 - 1
y - 6x = 23

3) Put your equation in the form Ax+By=C.
y - 6x = 23
-6x + y = 23

-------

Answer: -6x + y = 23

A = -6, B = 1, C = 23

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

$x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

3 years ago

What is the exponential function modeled by the following table?

Ierofanga [76]

$\bf \begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2&\stackrel{3^2+1}{10}\\
3&\stackrel{3^3+1}{28}\\
4&\stackrel{3^4+1}{82}
\end{array}\implies f(x)=3^x+1$

8 0

3 years ago

Help Please i'm begging for help!!!!!!!!

stealth61 [152]

X^2 + yz......x = 5, y = -3, z = 2
now we sub
5^2 + (-3)(2) =
25 + (-6) =
25 - 6 =
19

5 0

3 years ago

Trina planted plants in her garden last week. She planted twice as many cucumbers as zucchini and eight more tomatoes than cucum

maxonik [38]

Answer:

7 Zuchini, 14 Cucumbers and 22 Tomatoes plants.

Step-by-step explanation:

Let the number of tomatoes=t
Let the number of cucumber planted=c
Let the number of zucchini planted=z
Total Number of Plants=43

She planted twice as many cucumbers as zucchini, this is written as:

c=2z

She also planted eight more tomatoes than cucumbers, this is written as:

t=c+8=2z+8

In total, she planted 43 plants

Therefore:

z+(2z)+(2z+8)=43

5z+8=43

5z=43-8

5z=35

Divide both sides by 5

z=7

Number of Cucumbers, c=2z=2 X 7 =14

Number of Tomatoes, t=c+8=14+8=22

Therefore, she planted 7 Zuchini, 14 Cucumbers and 22 Tomatoes plants.

3 0

3 years ago

The large rectangle below represents one whole. What percent is represented by the shaded area? (URGENT)

nikitadnepr [17]

Answer:

40%

Step-by-step explanation:

The whole rectangle is split into 5 parts. Two out of 5 parts are shaded.

Set up a fraction:

$\frac{\text{Shaded}}{\text{Whole}}=\frac{2}{5}$

Convert into a decimal:

$\frac{2}{5}= 0.4$

Multiply the decimal by 100 to get the percent:

$0.4*100=40$

So, forty percent of the rectangle is shaded.

Hope this helps.

4 0

3 years ago

Read 2 more answers