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2 years ago

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Given that the first term is LaTeX: t_1=2t 1 = 2, and the recursive definition is LaTeX: t_{n+1}=3^{\left(t_n\right)}t n + 1 = 3

( t n ), what would be the 2nd term (LaTeX: t_2t 2).

2 answers:

salantis [7]2 years ago

8 0

<em>*100% CORRECT ANSWERS</em>

alexandr402 [8]2 years ago

5 0

Answer:

the correct answer is 9

Step-by-step explanation:

took the test and it was correct

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Which point on the x-axis lies on the line that passes through point P and is perpendicular to line MN? (0, 1) (0, 4) (1, 0) (4,

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I need to see line MN and point P first on a graph.

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Please help me solve problem 8

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The answer is A because when a question asks how much is left it typically means that you will need to subtract.

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Pleeeeeeeeaaaseeeeee help meeeeeeee!!!!!!!!!

zaharov [31]

Answer:

Option D.

$A =96\pi\ cm^2$

Step-by-step explanation:

The area of the circular bases is:

$A_c = 2\pi(a) ^ 2$

Where

$a=4\ cm$ is the radius of the circle

Then

$A = 2\pi(4) ^ 2$

$A = 32\pi\ cm^2$

The area of the rectangle is:

$A_r=b * 2\pi r$

Where

$b=8\ cm$

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Then the area of the rectangle is:

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$A_r=64\pi\ cm^2$

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$A = A_c + A_r\\\\A = 32\pi\ cm^2 + 64\pi\ cm^2\\\\$

$A =96\pi\ cm^2$

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3 years ago

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Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u> $y = log_{b} (x)$ <u><em></em></u>

<em>x 1/8 1/4 1/2 1 2</em>

<em>y -3 -2 -1 0 1</em>

<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

i)

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em> $\frac{1}{4}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{4} )$ <em></em>

<em></em> $y = log_{2} (2^{-2} )$ <em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em> $\frac{1}{2}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{2} )$ <em></em>

$y = log_{2} (2^{-1} )$

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1 given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (1 )$ <em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em> $2$ <em> given b > 1 so we can choose b = 2</em>

$y = log_{2} (2 )$

<em>y = 1</em>

<em></em>

<u><em>Final answer:-</em></u>

<u><em>The satisfied table of the given function</em></u>

<em>x 1/8 1/4 1/2 1 2</em>

<em>y -3 -2 -1 0 1</em>

<em></em>

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Scrat [10]

I hope this helps you

?=10×10

?=100

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