Answer:
yes to both
Step-by-step explanation:
(1) For y=1, and x=a, ...
a² + 1² ≤ 3
-√2 ≤ a ≤ √2 . . . . . subtract 1 and take the square root
All values of "a" are less than 2 inside the circle.
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(2) For y=4 and x=a, ...
2·4 +4·a = 10
4a = 2 . . . . . . . subtract 8
a = 1/2 . . . . . . .divide by 4
The value of "a" for point (a, 4) on the line is less than 2.
Answer:
22cm²
Step-by-step explanation:
For the area of triangle,
base = 2 + 2 + 2 = 6cm
height = 4cm
Area = 1/2 x base x height
= 1/2 x 6 x 4
= 12cm²
For area of the rectangle,
length = 5cm
breadth = 2cm
Area = length x breadth
= 5 x 2
= 10cm²
Area of compound shape = 12 + 10 = 22 cm²
1. 4i x -10i = -40ii
ii = i^2 = -1
-40*-1 = 40
2. -6-9 = -15
5i- - 5i = 5i + 5i = 10i
answer = -15 +10i
3. raise both sides to the 3rd, and solve for x. x = -12
4. the equation would be x^2+36 =0
Step-by-step explanation:
-k + 4(k + 1) = 2k
-k + 4k + 4 = 2k
-k + 4k - 2k = -4
(-1 + 4 - 2)k = -4
k = -4
