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madreJ [45]
3 years ago
13

Given that the first term is LaTeX: t_1=2t 1 = 2, and the recursive definition is LaTeX: t_{n+1}=3^{\left(t_n\right)}t n + 1 = 3

( t n ), what would be the 2nd term (LaTeX: t_2t 2).

Mathematics
2 answers:
salantis [7]3 years ago
8 0

<em>*100% CORRECT ANSWERS</em>

alexandr402 [8]3 years ago
5 0

Answer:

the correct answer is 9

Step-by-step explanation:

took the test and it was correct

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What is the equation of the line that passes through the point (-8,0)and has a slope of -1/4
Dahasolnce [82]

Answer:

y = -1/4x - 2

Step-by-step explanation:

I'm going to write this equation in slope intercept form, which looks like this: y = mx + b. First, write the equation using the slope given. It should look like this:

y = -1/4x + b

Next, you must find the y intercept by plugging in the point to the equation. This is what it looks like: 0 = -1/4(-8) + b. Multiply -1/4 by -8 to get 2. This is what your equation should look like now: 0 = 2 + b. Subtract 2 from both sides of the equation to get -2 = b. Go back to your original equation and plug -2 in for b. This is your final equation:

y = -1/4x - 2

Hope this helped!

8 0
3 years ago
If triangle DEF is classified as equilateral, which statement must be true?
patriot [66]

Answer:

all three sides are congruent.

Step-by-step explanation:

it is equiangular.

sides are equal.

angles are equal.

all three sides are congruent.

6 0
3 years ago
Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how
Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

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Where is the picture? If you could add your picture I’d be glad to help you!! :)
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