The employee's gross pay
$726.80
Is there a picture of the ramp?
To easily find the slope and y intercept of the line, put it in slope intercept form by rearranging the variables around.
6x-7y = 2
6x - 7y + 7y = 2 + 7y
6x = 7y + 2
6x - 2 = 7y + 2 - 2
7y = 6x - 2
7y/7 = 6x/7 - 2/7
Y = 6/7(X) - 2/7
Y = 6/7x - 2/7
Slope = m = 6/7
Y intercept = b = -2/7
(0, -2/7).
<span>The volume of the cylinder will be 2</span>π
As shown in figure, R is the base
radius of the cylinder.
H is the height of the cylinder.
Given: H = diameter of the base of
cylinder.
Now, diameter of the base = 2R
So, H = 2R
<span>Volume of cylinder = π×</span>
×H
<span> = π×</span>×(2R)
<span> = 2 π </span> cubic units.
Answer:
The first thing you should do for this case is to draw the ordered pairs in the plane and join the points.
The area you are looking for is the area of a rectangle plus the area of a triangle.
Thus, the total area will be
At = (8) * (4.5) + (1/2) * (4) * (2.5) = 41
answer
the area of the city is 41 units^2
Step-by-step explanation:
41 square miles If you draw the outline of the city, you'll realize that if you draw a line from point B to point D, that you can subdivide the city into a triangle and a trapezoid. After performing the division, you can then calculate the area of both polygons and the add their areas together. So first, let's deal with the trapezoid ABDE. The area of a trapezoid is the average of the length of the parallel sides multiplied by the height. The parallel sides are AB and DE. So: ((18-10)+(14-10))*(9-4.5)/2 =(9 + 4)*(4.5)/2 = 12*4.5/2 = 27 Now for the area of triangle BCD. The area of a triangle is 0.5*b*h where b is the base and h the height. I'll use BC as the base and the distance from BC to D as the height. So: (9-2)*(18-14)/2 = 7*4/2 = 14 And now to add the areas. 27 + 14 = 41 So the area of the city is 41 square miles. Note: The subdivision used is not the only possible subdivision, just one of the easier ones. I could have divided the city area into 3 triangles ABE, BDE, and BCD and solved it that way instead. It was just a happy coincidence that AB and DE were parallel and as such I was able to use trapezoid ABDE instead of the two triangles ABE and BDE.
