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3 years ago

Simplify if possible: (2/9)^3

Mathematics

1 answer:

adoni [48]3 years ago

6 0

(2/9)³=8/729
That's your answer.
[So big....)

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What mixed number can this improper fraction be converted to 5/2

BigorU [14]

The improper fraction 5/2 can be converted to the mixed number 2 1/2

4 0

3 years ago

Determine the slope between -2,6 3,4

andrew11 [14]

The slope is -999’inc because yssjjdidijdnxjdnxnnxkxkx

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3 years ago

Solomon can buy four sodas for $6 how much would 6 sodas cost

Bad White [126]

Answer:

6 soda's will cost $9.

Step-by-step explanation:

4 soda's costs $6.

Find the amount 2 soda's will cost. Divide 2 from both sides.

(4)/2 = 2

(6)/2 = 3

2 soda's will cost $3.

Now, solve for the cost for 6 soda's by multiply 3 to both sides.

2(3) = 6

3(3) = 9

6 soda's will cost $9.

7 0

4 years ago

Read 2 more answers

Can someone answer with steps and explanation? Thanks.

12345 [234]

Answer:

$BC=9\sqrt{3}\approx15.59\text{ units}$

Step-by-step explanation:

Since Segment BOA is a diameter:

$m\angle ACB=90$

Arc Ac and Arc CB are in a ratio of two to four. Since Segment BOA is a diameter, Arc ACB measures 180°. Letting the unknown value be x, we can write that:

$2x+4x=180$

Hence:

$x=30$

Thus, Arc CB = 120°. By the Inscribed Angle Theorem:

$\displaystyle m\angle A=\frac{1}{2}\left(\stackrel{\frown}{CB}\right)=\frac{1}{2}\left(120)=60$

Therefore, ΔABC is a 30-60-90 triangle. Its sides are in the ratios shown in the image below.

Since AC is opposite from the 30° triangle, let AC = a.

We are given that AC = 9. Hence, a = 9.

BC is opposite from the 60° angle and it is given by a√3. Therefore:

$BC=9\sqrt{3}\approx15.59\text{ units}$

7 0

3 years ago

Find the quotient -44a^3b^4 - 64a^4b3 - 84ab ___________________ -4ab

Aliun [14]

When you divide a variable with an exponent by a variable with an exponent, you subtract the exponents (only if the bases/variables are the same)

For example:

$\frac{x^2}{y^2}$ Since they have different variables (x and y), you can't simplify this anymore

$\frac{x^5}{x^3} = x^{5-3}=x^2$

$\frac{z^3x^7}{z^2yx^2} = (\frac{1}{y})(z^{3-2})(x^{7-2}) = (\frac{1}{y} )(z^1)(x^5) = \frac{zx^5}{y}$

( if the exponent happens to come out negative, you have to move the variable and the exponent to the other side of the fraction to make the exponent positive)

Ex:

$\frac{x^2}{x^4} =x^{2-4}=x^{-2} = \frac{1}{x^2}$

$\frac{-44a^3b^4-64a^4b^3-84ab}{-4ab}$ SInce they all have a common factor of 4, you can divide out -4

$\frac{11a^3b^4+16a^4b^3+21ab}{ab}$

If you follow the steps from ^^^^^^^, you should get

$11a^2b^3+16a^3b^2+21$

7 0

3 years ago