Answer:
6x^3 - 2x^2 -11x +4
Step-by-step explanation:
(3x-4)(2x^2+2x-1)
Multiply 3x by the second term
3x* (2x^2+2x-1)
6x^3 +6x^2 -3x
Multiply -4 by the second term
-4*(2x^2+2x-1)
-8x^2 -8x+4
Add these together, lining up the terms
6x^3 +6x^2 -3x
-8x^2 -8x+4
----------------------------------
6x^3 - 2x^2 -11x +4
The first equation is 6x - 2y = 10. To solve for y, you will use inverse (opposite) operations to undo what is happening to y. Please see the steps below for the work.
6x - 2y = 10
-6x -6x
<u>-2y </u>= <u>(-6x + 10)</u>
-2 -2
y = 3x - 5
Answer:
just using normal x and y coordinates
4x + 2y = 36
where x = 5
that is 4×5 = 20
where y = 8
that is 2×8 = 16.
Ok so we want to cross multiply.
To do this you know 4/9=2$ so now you want to know 1=x$
When you do this you get $5