Help please

Mathematics

1 answer:

Svetlanka [38]4 years ago

5 0

Well first of you need to know that on a straight line there should be 180 degrees. Also a triangle has 180 degrees in total. Now if this is to scale then you can always measure the angle BCA and explain how you took that away from 180 to get whatever. Assuming otherwise i don't know how one can actually complete this question without any measurements, at least one and it would be something anyone can complete. Even if you didn't have anything it should be a equilateral triangle or isosceles. That way you can work out the inside sides than the exterior. But since it's not, I'm not to sure.

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Consider a regular pyramid A with a square base and a right circular cone B.

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Answer:

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Step-by-step explanation:

$\text{Volume of a Square Pyramid }=\frac{1}{3} \times l^2 \times Height\\\\ \text{Volume of a Cone }=\frac{1}{3} \pi r^2 \times Height$

Given that the two solids have the same volume

$\frac{1}{3} \times l^2 \times Height=\frac{1}{3} \pi r^2 \times Height$

If the length of a side of the square base of pyramid A is the same as the base radius of cone B. i.e l=r

$\frac{1}{3} \times l^2 \times $Height of Pyramid=$\frac{1}{3} \pi l^2 \times $Height of cone$\\\\$Cancel out $ \frac{1}{3} \times l^2$ on both sides\\\\Height of Pyramid= \pi \times $ Height of cone$$