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lesya692 [45]
3 years ago
5

Which figure has exacly 2 sets of parallel sides and no perpendicular sides

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0
Square. Because there is 2 right angles there are only 4 sides all which are perpendicular
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Expand the following:
Jet001 [13]
Yes that is correct good job
3 0
3 years ago
HELP PLEASE this is due tomorrow i need help with numbers 1, 2, and 3
Mama L [17]

Answer:

1, -5/2, 3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5
Marianna [84]
\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}

\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)

of course, you can always use  (x-1)(x-1)(2x+1)(x²-4x+5)  as well.
7 0
3 years ago
Answer Please!!<br>I will brainlist him/her​
NeTakaya

Answer:

11 : 4

12 : 4 / 4

13 : 6/6

14 : 12 / 4

15: 9/3

16: 4/4

17: 15/5

18: 6/2

19: 10/5

20: 6/6

5 0
2 years ago
-4(y - 2) = 12<br><br> solve for y, thanks
andrezito [222]

Answer:

-1

Step-by-step explanation:

-4(y-2)=12

-4y+8=12

-4y=4

y= -1

8 0
3 years ago
Read 2 more answers
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