Question

URGENT 100 points

Answer 1

Answer:

see below

Step-by-step explanation:

Part A

We know the slope is change in y over change in x

m = (y2-y1)/(x2-x1)

m = ( 475 - 325)/(10 -0)

= 150 /10

= 15

The slope is the change in the bank balance per day

The balance is increasing 15 dollars per day

Part B

point slope is y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

We can use any point

y - 400 = 15(x-5)

y = mx+b is slope intercept

The slope ,m, is 15 and the y intercept is 325

y = 15x+325

standard form is ax+by =c

y = 15x+325 where a>0 and a,b,c are integers

-15x +y = 325

15x -y = -325

Part C

function notation is replacing y with f(x)

f(x) = 15x+325

Part D

Let x = 12

f(12) = 15*12 +325

=180+325

= 505

Answer 2

Answer:

see below

Step-by-step explanation:

Part A

We know the slope is change in y over change in x

m = (y2-y1)/(x2-x1)

m = ( 475 - 325)/(10 -0)

   = 150 /10

  = 15

The slope is the change in the bank balance per day

The balance is increasing 15 dollars per day

Part B

point slope is y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

We can use any point

y - 400 = 15(x-5)

y = mx+b is slope intercept

The slope ,m, is 15 and the y intercept is 325

y = 15x+325

standard form is ax+by =c

y = 15x+325 where a>0 and a,b,c are integers

-15x +y = 325

15x -y = -325

Part C

function notation is replacing y with f(x)

f(x) = 15x+325

Part D

Let x = 12

f(12) = 15*12 +325

       =180+325

      = 505