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3 years ago

URGENT 100 points

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Answer:

see below

Step-by-step explanation:

Part A

We know the slope is change in y over change in x

m = (y2-y1)/(x2-x1)

m = ( 475 - 325)/(10 -0)

= 150 /10

= 15

The slope is the change in the bank balance per day

The balance is increasing 15 dollars per day

Part B

point slope is y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

We can use any point

y - 400 = 15(x-5)

y = mx+b is slope intercept

The slope ,m, is 15 and the y intercept is 325

y = 15x+325

standard form is ax+by =c

y = 15x+325 where a>0 and a,b,c are integers

-15x +y = 325

15x -y = -325

Part C

function notation is replacing y with f(x)

f(x) = 15x+325

Part D

Let x = 12

f(12) = 15*12 +325

=180+325

= 505

mars1129 [50]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

Part A

We know the slope is change in y over change in x

m = (y2-y1)/(x2-x1)

m = ( 475 - 325)/(10 -0)

= 150 /10

= 15

The slope is the change in the bank balance per day

The balance is increasing 15 dollars per day

Part B

point slope is y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

We can use any point

y - 400 = 15(x-5)

y = mx+b is slope intercept

The slope ,m, is 15 and the y intercept is 325

y = 15x+325

standard form is ax+by =c

y = 15x+325 where a>0 and a,b,c are integers

-15x +y = 325

15x -y = -325

Part C

function notation is replacing y with f(x)

f(x) = 15x+325

Part D

Let x = 12

f(12) = 15*12 +325

=180+325

= 505

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Step-by-step explanation:

We need to select all the expression that are equivalent to 1.5 square

1.5 square = 1.5²

= 1.5 × 1.5

= 2.25

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Which statements are always true regarding the diagram?

Gekata [30.6K]

Answer:

m∠5+m∠6=180°

m∠2+m∠3=m∠6

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Step-by-step explanation:

Verify each option

case A) we have

m∠5+m∠3=m∠4 ----> equation A

we know that

m∠3+m∠4=180° -----> by supplementary angles

m∠4=180°-m∠3 ----> equation B

substitute equation B in equation A

m∠5+m∠3=180°-m∠3

m∠5+m∠3+m∠3=180°

This equation is true when m∠2=m∠3

therefore

Is not always true

case B) we have

m∠3+m∠4+m∠5=180° ----> equation A

we know that

m∠3+m∠4=180° -----> by supplementary angles

m∠4=180°-m∠3 ----> equation B

substitute equation B in equation A

m∠3+(180°-m∠3)+m∠5=180°

m∠5=0°

This option is not true

case C) we have

m∠5+m∠6=180°

we know that

m∠5 and +m∠6 are supplementary angles

Their sum is always 180 degrees

therefore

This option is always true

case D) we have

m∠2+m∠3=m∠6 -----> equation A

we know that

m∠5+m∠6=180° ----> by supplementary angles

m∠6=180°-m∠5 ----> equation B

substitute equation B in equation A

m∠2+m∠3=180°-m∠5

m∠2+m∠3+m∠5=180°

Remember that the sum of the interior angles of a triangle must be equal 180 degrees

therefore

This option is always true

case E) we have

m∠2+m∠3+m∠5=180°

Remember that the sum of the interior angles of a triangle must be equal 180 degrees

therefore

This option is always true

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