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3 years ago

URGENT 100 points

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Answer:

see below

Step-by-step explanation:

Part A

We know the slope is change in y over change in x

m = (y2-y1)/(x2-x1)

m = ( 475 - 325)/(10 -0)

= 150 /10

= 15

The slope is the change in the bank balance per day

The balance is increasing 15 dollars per day

Part B

point slope is y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

We can use any point

y - 400 = 15(x-5)

y = mx+b is slope intercept

The slope ,m, is 15 and the y intercept is 325

y = 15x+325

standard form is ax+by =c

y = 15x+325 where a>0 and a,b,c are integers

-15x +y = 325

15x -y = -325

Part C

function notation is replacing y with f(x)

f(x) = 15x+325

Part D

Let x = 12

f(12) = 15*12 +325

=180+325

= 505

mars1129 [50]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

Part A

We know the slope is change in y over change in x

m = (y2-y1)/(x2-x1)

m = ( 475 - 325)/(10 -0)

= 150 /10

= 15

The slope is the change in the bank balance per day

The balance is increasing 15 dollars per day

Part B

point slope is y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

We can use any point

y - 400 = 15(x-5)

y = mx+b is slope intercept

The slope ,m, is 15 and the y intercept is 325

y = 15x+325

standard form is ax+by =c

y = 15x+325 where a>0 and a,b,c are integers

-15x +y = 325

15x -y = -325

Part C

function notation is replacing y with f(x)

f(x) = 15x+325

Part D

Let x = 12

f(12) = 15*12 +325

=180+325

= 505

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Answer:

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Step-by-step explanation:

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3 years ago

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Help.........................<br><br>

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

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