Answer Please!!<br>I will brainlist him/her

Could you explain this please. Than You.<br>4/7 × 50/9 × 27/16

Vladimir79 [104]

That is the answer to it

7 0

3 years ago

Two marathon runners run the full distance of the marathon, approximately 26 miles, in 4 hours.

xxTIMURxx [149]

Answer:

6.5 miles in 1 hour and they will run 75% of the full distance in 1 hour.

Step-by-step explanation:

The distance covered by two marathon runners = 26 miles

They takes 4 hours

We need to find how many miles did they run in 1 hour

In 4 hour, the distance covered is 26 miles

To find distance covered in 1 hour, divide 26 by 4 such that.

$d=\dfrac{26}{4}\\\\d=6.5\ \text{miles/hour}$

So, they will cover 6.5 miles in 1 hour.

For percentage,

$\%=\dfrac{26-6.5}{26}\times 100\\\\=75\%$

So, they will run 75% of the full distance in 1 hour.

8 0

3 years ago

Someone please do this one for me !!!!

oee [108]

Answer:

Plot the points in black and connect them.

Plot the point in blue and count up 3 and to the right 1. Plot and connect the points.

Step-by-step explanation:

Using your cursor/mouse, you will first choose the color black. Then you will plot the points given to you (2,2) and (5,8) by first finding the x-coordinate of (x,y). Start at 2 on the x-axis. Follow the grid line up two units so you will also be at the 2 on the y-axis. Plot or draw a dot/circle on this grid line. Go back to the x-axis and start again at 5 on the x-axis. Follow the grid line up eight units so you will also be at the 8 on the y-axis. Plot or draw a dot/circle on this grid line. Connect the dots for your line.

Using your cursor/mouse, you will choose the color blue. Then you will plot the point given to you (10,5) by first finding the x-coordinate of (x,y). Start at 10 on the x-axis. Follow the grid line up five units so you will also be at the 5 on the y-axis. Plot or draw a dot/circle on this grid line. Instead of plotting another point. This time you will count from the blue point up three units and over to the right one. Mark this grid line as a point. Now connect them.

6 0

3 years ago

Are the given lenghts a right triangle? 28, 53,45

aalyn [17]

Yes that should be correct

5 0

3 years ago

Read 2 more answers

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

3 years ago

Answer Please!!I will brainlist him/her​

Answer Please!!I will brainlist him/her