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Leno4ka [110]
3 years ago
11

A city’s bus line is used more as the urban population density increases. The more people in an area, the more likely bus lines

will be utilized. The population of Belmont, MA, is 24,729 and covers an area of 4.66 mi2. The population of Easton, MA, is 23,112 and covers an area of 28.4 mi2. Which city’s residents are more likely to use public buses? Explain. The residents of Belmont are more likely to use public transportation because the city has the highest population density. The residents of Easton are more likely to use public transportation because the city has the highest population density. The residents of both cities will not use the bus line because the population density is too high. The residents of both cities are equally likely to use public transportation because the population densities are equal.
Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

(A) The residents of Belmont are more likely to use public transportation because the city has the highest population density.

Step-by-step explanation:

correct on edge

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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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Answer:

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Step-by-step explanation:

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Mazyrski [523]
First find the area of the parallelogram


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Then find area of kite

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