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Kryger [21]
3 years ago
12

Can someone help me on this

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
I don't know what the first two blanks are asking for, but the last one should be Alternate Exterior Angles Property of Congruence (AEAPC).
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Is (-3,2)(−3,2)left parenthesis, minus, 3, comma, 2, right parenthesis a solution of -4x -10y < -9−4x−10y<−9minus, 4, x, m
r-ruslan [8.4K]

Answer:

The answer to your question is The point (-3, 2) is not a solution

Step-by-step explanation:

Inequality

                                   - 4x - 10y < - 9

-point (-3, 2)

Process

1.- To solve this problem, just substitute the point in the inequality and simplify

a) Substitution

                                    -4(-3) - 10(2) < - 9

b) Simplification

                                    12 - 20 < - 9

c) Result

                                        - 8 < - 9

This is false, -8 > -9

7 0
3 years ago
To find the quotient of 3 divided by one-sixth, multiply 3 by what
Reptile [31]
You have to multiply 3 x 6.

7 0
3 years ago
Read 2 more answers
Convert 25/8 into a mixed number
motikmotik
Changing improper fractions to mixed form or mixed numbers is a very simple thing. You just have to follow the following:
Then write Let us have 25/8. <span><span>
1.       </span><span>Divide the numerator (top number)  by the denominator (number below the bar). </span></span> Simply divide 25 by 8. 25 ÷ 8 = n
We can have 3 and 1 as a remainder. So, the answer will be 3 and 1/8. <span><span>

2.       </span> <span>Write down the whole number answer. 
Since we have 3 as the whole number answer, write it down. And;</span></span> <span><span>

3.       </span><span> Write down any remainder above the denominator, like this:</span></span> 3 and 1 (remainder) over 8 (denominator of the given improper fraction). That is, 3 1/8  


3 0
4 years ago
We have 6 face red cards (JQK x 2) and 16 black cards, so a total of 22 cards.The red face cards and the black cards numbered 2-
In-s [12.5K]

Answer:

I dont know

Step-by-step explanation:

only doing it for points

5 0
3 years ago
How do I solve this absolute value in quality problem <br><br> |2t + 2/3|≤4
xenn [34]

Answer: -7/3≤t≤5/3

Step-by-step explanation:

|2t + 2/3|≤4

2t + 2/3≤4

(2t + 2/3≤4)*3

6t+2≤12

6t≤10

t≤10/6

<u>t≤5/3</u>

2t + 2/3>=-4

(2t + 2/3>=-4)*3

6t + 2>=-12

6t>=-14

t>=-14/6

<u>t>=-7/3</u>

-7/3≤t≤5/3

6 0
2 years ago
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