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Kryger [21]
3 years ago
12

Can someone help me on this

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
I don't know what the first two blanks are asking for, but the last one should be Alternate Exterior Angles Property of Congruence (AEAPC).
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A store owner paid $15 dollars for a book. she marked up the price of the book by 40% to determine it's selling price.
Tcecarenko [31]
A) $15 ÷ 40% =
15×.4= 6
15+6= 21

B) $38 × .25=9.5
38-9.5=28.50

28.50×.06=1.71
28.50+1.17=30.21

I think this is how you do it. would wait for other answers as well to double check.
6 0
4 years ago
Read 2 more answers
Solving a system of linear equations using the substitution method. <br> 5x+4y=-26<br> 5-x=-6y
yan [13]
Solve for x in 2nd equation
times -1 both sides
x-5=6y
add 5
x=6y+5

sub

5(6y+5)+4y=-26
30y+25+4y=-26
34y+25=-26
minus 25 both sides
34y=-51
divide both sides by 34
y=-3/2
sub back

x=6y+5
x=6(-3/2)+5
x=-18/2+5
x=-9+5
x=-4


(-4,-3/2) is solution
5 0
3 years ago
Read 2 more answers
Carl, Gilda, Conroy, and Kyla are the four candidates in a school election. Carl received 1/5 of the votes, Gilda received 5% of
Juliette [100K]
Firstly, we can convert all of the fractions into percentages. To do this, we need to make the denominator of the fraction 100, and whatever we do to the denominator we must also do to the numerator.

5 x 20 = 100
1 x 20 = 20.

So Carl recieves 20/100 or 20% of the votes.

4 x 25 = 100
1 x 15 = 25

So Conroy receives 25/100 or 25% of the votes.

If we add these together and Gilda's 5%, we get 50%. Since there are 100% votes overall, we need to do 100 - 50 = 50.
 
Kyla receives 50% of the votes.
8 0
3 years ago
Read 2 more answers
What’s 4 and 3/16 + 1 and 1/10 in simplest form?? PLEASE NEED THIS ASSAP pleaseeee
mrs_skeptik [129]
5 and 23/80 is the answer
3 0
3 years ago
Read 2 more answers
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
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