3 years ago

Can someone help me on this

1 answer:

3 0

I don't know what the first two blanks are asking for, but the last one should be Alternate Exterior Angles Property of Congruence (AEAPC).

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A quadratic function y=f(x)y=f(x) is plotted on a graph and the vertex of the resulting parabola is (5, -6)(5,−6). What is the v

MariettaO [177]

Answer:

The vertex is at (5,4).

Step-by-step explanation:

I graphed both of the functions on the graph below.

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2 years ago

give the slope of the line (if it exists) and the y intercept (if it exists) and graph the line 5y=3. what is the slope?

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Answer:

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Y=–6x+2<br> –12x – 2y=–4<br> How many solutions does this linear system have?

DerKrebs [107]

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

<h3>Linear equation</h3>

y = -6x + 2

-12x - 2y = -4

Substitute y = -6x + 2 into (2)

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

Solve for x

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

Substitute into (2)

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

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The answer is 16 degrees to your problem.

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Answer:

$1477.033\\$

Step-by-step explanation:

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