Keisha is pedaling her bicycle at a velocity of .10 km/min. How far will she travel in two hours?

After finishing a sprint tawanda experiences painful cramps

ddd [48]

Her muscle cramps are most likely due to a temporary deficit of; Adenosine triphosphate (ATP)

<h3>What are the causes of Cramps?</h3>

The potential causes of cramp could be because of dehydration, low levels of certain minerals (magnesium, potassium, calcium, and sodium, although the evidence has been mixed), and reduced blood flow through muscles attendant in prolonged sitting or lying down.

Now, in this Tawanda's case, we see that it is more like a pain to her calf muscles and as such we can say that the cause is from a deficit of ATP because muscle relaxation is an adenosine triphosphate (ATP)-dependent active process, actin and myosin chains do not disengage, causing an electrically silent cramp.

Thus, from the above we can conclude that her muscle cramps are most likely due to a temporary deficit of; Adenosine triphosphate (ATP)

Complete question is;

After Tawanda finishes a sprint and suffers great pain in her calf muscles. Her muscle cramps are most likely due to a temporary deficit of?

Read more about Causes of Cramps at; brainly.com/question/1952660

#SPJ1

4 0

1 year ago

For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an

Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

$\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}$

where;

n = Number of electrons = 2
$\mathbf{E_o}$ = Initial voltage = 0.77 V
$\mathbf{E_{cell}}$ = Cell voltage = 0.78 V
$\mathbf{[Mn^{2+}]}$ = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

$\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}$

$\mathbf{Fe^{2+} =0.02297 \ M }$

Learn more about using the Nernst equation here:

brainly.com/question/24258023

6 0

2 years ago

Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o

Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

Carbon (C): 47.37 grams
Hydrogen (H): 10.59 grams
Oxygen (O): 42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Carbon (C): $\frac{47.37 grams}{12 \frac{g}{mole} }$ = 3.95 moles
Hydrogen (H): $\frac{10.59 grams}{1 \frac{g}{mole} }$ = 10.59 moles
Oxygen (O): $\frac{42.04 grams}{16 \frac{g}{mole} }$ = 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Carbon (C): $\frac{3.95 moles}{2.63 moles }$ = 1.5
Hydrogen (H): $\frac{10.59 moles}{2.63 moles }$ = 4
Oxygen (O): $\frac{2.63 moles}{2.63 moles }$ = 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

Carbon (C): 1.5× 2= 3
Hydrogen (H): 4× 2= 8
Oxygen (O): 1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

Learn more about empirical formula:

brainly.com/question/21081934?referrer=searchResults

brainly.com/question/5115389?referrer=searchResults

brainly.com/question/4594902?referrer=searchResults

brainly.com/question/13725914?referrer=searchResults

brainly.com/question/13599051?referrer=searchResults

brainly.com/question/13112542?referrer=searchResults

3 0

2 years ago